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A solution containing 10 per dm3 of urea is isotonic with a 5% solution of a non volatile solute is - 1) 250 gmol -1 2) 300gmol -1 3)350gmol-1 4) 400gmol -1?
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A solution containing 10 per dm3 of urea is isotonic with a 5% solutio...
10 g per dm^3 of urea is isotonic with 5% solution of a non-volatile solute. Hence, their molar concentrations are, equal to each other.
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A solution containing 10 per dm3 of urea is isotonic with a 5% solutio...
Isotonic Solutions:
An isotonic solution is a solution that has the same osmotic pressure as the solution it is being compared to. In other words, it has the same concentration of solutes as the reference solution. Isotonic solutions are commonly used in medical applications, such as intravenous fluids.
Non-Volatile Solute:
A non-volatile solute is a solute that does not easily evaporate or vaporize. This means that the concentration of the solute remains constant regardless of changes in temperature or pressure.
Now, let's analyze the given information and find the molar mass of the non-volatile solute in the 5% solution.
Step 1: Understanding the Concentration Units
The concentration of the urea solution is given as 10 per dm3. This means that there are 10 moles of urea in 1 dm3 (or 1000 cm3) of the solution.
The concentration of the non-volatile solute is given as 5%. This means that there are 5 grams of the solute in 100 grams of the solution.
Step 2: Calculating the Molar Mass of the Non-Volatile Solute
To find the molar mass of the non-volatile solute, we need to convert the concentration from grams to moles.
Given that there are 5 grams of the solute in 100 grams of the solution, we can calculate the number of moles of the solute as follows:
Moles of solute = Mass of solute / Molar mass of solute
5 grams / (5/100) = 100 grams
Therefore, there are 100 moles of the solute in 100 grams of the solution.
Step 3: Comparing the Concentrations
Since the urea solution is isotonic with the 5% solution of the non-volatile solute, it means that the concentrations of the two solutions are equal.
The concentration of the urea solution is given as 10 per dm3, which is equivalent to 10 moles per liter.
Therefore, the molar mass of the non-volatile solute must be equal to the concentration of the urea solution, which is 10 mol/dm3.
Final Answer:
The molar mass of the non-volatile solute in the 5% solution is 10 gmol-1. Option 1 (250 gmol-1) is not the correct answer. The correct answer is option 2 (300 gmol-1).
An isotonic solution is a solution that has the same osmotic pressure as the solution it is being compared to. In other words, it has the same concentration of solutes as the reference solution. Isotonic solutions are commonly used in medical applications, such as intravenous fluids.
Non-Volatile Solute:
A non-volatile solute is a solute that does not easily evaporate or vaporize. This means that the concentration of the solute remains constant regardless of changes in temperature or pressure.
Now, let's analyze the given information and find the molar mass of the non-volatile solute in the 5% solution.
Step 1: Understanding the Concentration Units
The concentration of the urea solution is given as 10 per dm3. This means that there are 10 moles of urea in 1 dm3 (or 1000 cm3) of the solution.
The concentration of the non-volatile solute is given as 5%. This means that there are 5 grams of the solute in 100 grams of the solution.
Step 2: Calculating the Molar Mass of the Non-Volatile Solute
To find the molar mass of the non-volatile solute, we need to convert the concentration from grams to moles.
Given that there are 5 grams of the solute in 100 grams of the solution, we can calculate the number of moles of the solute as follows:
Moles of solute = Mass of solute / Molar mass of solute
5 grams / (5/100) = 100 grams
Therefore, there are 100 moles of the solute in 100 grams of the solution.
Step 3: Comparing the Concentrations
Since the urea solution is isotonic with the 5% solution of the non-volatile solute, it means that the concentrations of the two solutions are equal.
The concentration of the urea solution is given as 10 per dm3, which is equivalent to 10 moles per liter.
Therefore, the molar mass of the non-volatile solute must be equal to the concentration of the urea solution, which is 10 mol/dm3.
Final Answer:
The molar mass of the non-volatile solute in the 5% solution is 10 gmol-1. Option 1 (250 gmol-1) is not the correct answer. The correct answer is option 2 (300 gmol-1).
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A solution containing 10 per dm3 of urea is isotonic with a 5% solution of a non volatile solute is - 1) 250 gmol -1 2) 300gmol -1 3)350gmol-1 4) 400gmol -1?
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A solution containing 10 per dm3 of urea is isotonic with a 5% solution of a non volatile solute is - 1) 250 gmol -1 2) 300gmol -1 3)350gmol-1 4) 400gmol -1? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A solution containing 10 per dm3 of urea is isotonic with a 5% solution of a non volatile solute is - 1) 250 gmol -1 2) 300gmol -1 3)350gmol-1 4) 400gmol -1? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solution containing 10 per dm3 of urea is isotonic with a 5% solution of a non volatile solute is - 1) 250 gmol -1 2) 300gmol -1 3)350gmol-1 4) 400gmol -1?.
A solution containing 10 per dm3 of urea is isotonic with a 5% solution of a non volatile solute is - 1) 250 gmol -1 2) 300gmol -1 3)350gmol-1 4) 400gmol -1? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A solution containing 10 per dm3 of urea is isotonic with a 5% solution of a non volatile solute is - 1) 250 gmol -1 2) 300gmol -1 3)350gmol-1 4) 400gmol -1? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solution containing 10 per dm3 of urea is isotonic with a 5% solution of a non volatile solute is - 1) 250 gmol -1 2) 300gmol -1 3)350gmol-1 4) 400gmol -1?.
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