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A person holding a rifle (mass of person and rifle together is 100kg) stands on a smooth surface and fires 10shots horizontally, in 5s .Each bullet has a mass of 10g with a muzzle velocity of 800m/s.The final velocity acquired by the person and the average force exerted on the person are. (a) -0.08m/s,16N (b)-0.8m/s,8N (c) -1.6m/s,16N?
Most Upvoted Answer
A person holding a rifle (mass of person and rifle together is 100kg) ...
By the law of momentum conservation:- 
=>P(iniitial) = P(final) 
=>mu1 + Mu2 = mv1 +Mv2 
=>0 + 0 = nmu + (M-nm)v 
=>10 x 10 x 10^-3 x 800 + (100 - 10 x 10 x 10^-3) x v 
=>v = -0.80 m/s {-ve just indicating the direction is opposite to the direction of bullets} 
By F = ∆P/∆t 
=>F = {10 x 10 x 10^-3 x 800}/5 = 16N

Hope it helps!!!!!
Community Answer
A person holding a rifle (mass of person and rifle together is 100kg) ...
Solution:

Given:
Mass of person and rifle (m1) = 100 kg
Mass of bullet (m2) = 10 g = 0.01 kg
Muzzle velocity of bullet (v) = 800 m/s
Number of shots fired (n) = 10
Time taken to fire the shots (t) = 5 s

1. Calculation of momentum of bullet:

Momentum of bullet = Mass of bullet x Velocity of bullet
= 0.01 kg x 800 m/s
= 8 Ns

2. Calculation of change in momentum:

Change in momentum = Momentum of bullet x Number of shots fired
= 8 Ns x 10
= 80 Ns

3. Calculation of recoil velocity:

According to the law of conservation of momentum, the total momentum before and after the firing of the bullets should be equal.

Initial momentum = m1v1
Final momentum = (m1 + n*m2)V

where V is the recoil velocity acquired by the person and m1v1 = (m1 + n*m2)V

V = (m1v1)/(m1 + n*m2)
= (100 kg x 0 m/s)/(100 kg + 10 x 0.01 kg x 800 m/s)
= 0 m/s

Therefore, the final velocity acquired by the person is -0.08 m/s (in the opposite direction).

4. Calculation of average force exerted on the person:

Average force exerted on the person = Change in momentum/Time taken
= 80 Ns/5 s
= 16 N

Therefore, the average force exerted on the person is 16 N.

Hence, the final velocity acquired by the person and the average force exerted on the person are -0.08 m/s and 16 N respectively. Therefore, the correct option is (a) -0.08m/s,16N.
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A person holding a rifle (mass of person and rifle together is 100kg) stands on a smooth surface and fires 10shots horizontally, in 5s .Each bullet has a mass of 10g with a muzzle velocity of 800m/s.The final velocity acquired by the person and the average force exerted on the person are. (a) -0.08m/s,16N (b)-0.8m/s,8N (c) -1.6m/s,16N?
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A person holding a rifle (mass of person and rifle together is 100kg) stands on a smooth surface and fires 10shots horizontally, in 5s .Each bullet has a mass of 10g with a muzzle velocity of 800m/s.The final velocity acquired by the person and the average force exerted on the person are. (a) -0.08m/s,16N (b)-0.8m/s,8N (c) -1.6m/s,16N? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A person holding a rifle (mass of person and rifle together is 100kg) stands on a smooth surface and fires 10shots horizontally, in 5s .Each bullet has a mass of 10g with a muzzle velocity of 800m/s.The final velocity acquired by the person and the average force exerted on the person are. (a) -0.08m/s,16N (b)-0.8m/s,8N (c) -1.6m/s,16N? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A person holding a rifle (mass of person and rifle together is 100kg) stands on a smooth surface and fires 10shots horizontally, in 5s .Each bullet has a mass of 10g with a muzzle velocity of 800m/s.The final velocity acquired by the person and the average force exerted on the person are. (a) -0.08m/s,16N (b)-0.8m/s,8N (c) -1.6m/s,16N?.
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