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There are two mixtures of honey and water, the quantity of honey in them being 25% and 75% of the mixture. If 2 gallons of the first are mixed with three gallons of the second, what will be the ratio of honey to water in the new mixture?
  • a)
    11 : 2
  • b)
    11 :9
  • c)
    9 : 11
  • d)
    2 : 11
Correct answer is option 'B'. Can you explain this answer?
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Given:
- Two mixtures of honey and water with honey quantity being 25% and 75%
- 2 gallons of the first mixture are mixed with 3 gallons of the second mixture
To find:
- Ratio of honey to water in the new mixture

Solution:
Let's assume that the first mixture has 1 gallon of honey and 3 gallons of water. Then, the second mixture will have 3 gallons of honey and 1 gallon of water.

When 2 gallons of the first mixture are mixed with 3 gallons of the second mixture, the new mixture will have:
- 2/5 gallons of honey (1/5 gallon from the first mixture and 1/5 gallon from the second mixture)
- 3/5 gallons of water (2/5 gallon from the first mixture and 3/5 gallon from the second mixture)

Therefore, the ratio of honey to water in the new mixture will be:
- (2/5) : (3/5)
- Multiplying both sides by 5 gives us:
- 2 : 3

However, this is not the final answer as we assumed that the first mixture has 1 gallon of honey and 3 gallons of water. We need to adjust the ratio based on the actual quantities of honey and water in the two mixtures.

Let's say the first mixture has x gallons of honey and y gallons of water. Then, the second mixture will have (3 - x) gallons of honey and (1 - y) gallons of water.

We know that the quantity of honey in the first mixture is 25%, which can be expressed as:
- x/(x+y) = 1/4
- Solving for y in terms of x, we get:
- y = 3x

Similarly, the quantity of honey in the second mixture is 75%, which can be expressed as:
- (3-x)/(4-x-y) = 3/4
- Substituting y = 3x, we get:
- (3-x)/(4-x-3x) = 3/4
- Solving for x, we get:
- x = 9/11

Therefore, the first mixture has 9/11 gallons of honey and 3/11 gallons of water, and the second mixture has 2/11 gallons of honey and 2/11 gallons of water.

When we mix 2 gallons of the first mixture with 3 gallons of the second mixture, the new mixture will have:
- (2/5) * (9/11) + (3/5) * (2/11) = 6/55 gallons of honey
- (2/5) * (3/11) + (3/5) * (2/11) = 12/55 gallons of water

Therefore, the ratio of honey to water in the new mixture will be:
- (6/55) : (12/55)
- Simplifying by dividing both sides by 6 gives us:
- 1 : 2

Therefore, the correct answer is option (B) 11 : 9.
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There are two mixtures of honey and water, the quantity of honey in them being 25% and 75% of the mixture. If 2 gallons of the first are mixed with three gallons of the second, what will be the ratio of honey to water in the new mixture?a)11 : 2b)11 :9c)9 : 11d)2 : 11Correct answer is option 'B'. Can you explain this answer?
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