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M times the mth term of an AP is equal to n times the nth term,then show that (m n)th term is 0?
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M times the mth term of an AP is equal to n times the nth term,then sh...
Let the first term of AP = a
common difference = d
We have to show that (m+n)th term is zero or a + (m+n-1)d = 0

mth term = a + (m-1)d
nth term = a + (n-1) d

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M times the mth term of an AP is equal to n times the nth term,then sh...
Proof that (m n)th term is 0 when M times the mth term equals n times the nth term:
- Let us consider an arithmetic progression (AP) with common difference d.
- The mth term of the AP is given by: a_m = a_1 + (m-1)d
- The nth term of the AP is given by: a_n = a_1 + (n-1)d

Given:
M times the mth term = n times the nth term
=> M(a_1 + (m-1)d) = n(a_1 + (n-1)d)

Expanding the above equation:
=> Ma_1 + M(m-1)d = na_1 + n(n-1)d
=> Ma_1 + Mmd - Md = na_1 + n^2d - nd

Rearranging the terms:
=> (Mm - n)n = (M - n)d

Since it is an AP, the common difference d is constant:
=> Mm - n = M - n
=> Mm = M

Therefore, (m n)th term is 0:
Since Mm = M, we have Mm - M = 0
Hence, the (m n)th term of the AP is 0.
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M times the mth term of an AP is equal to n times the nth term,then show that (m n)th term is 0?
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