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If x molecules are removed from 200mg N2O?
Verified Answer
If x molecules are removed from 200mg N2O?
Molecular mass of N₂O = 44
weight of N₂O = 200mg = 0.2g
moles of N₂O present = 0.2/44 = 4.55x10^(-3)
Let moles of N₂O removed = y
moles of N₂O remained = 2.89x10^(-3)
Thus 4.55x10^(-3) - y = 2.89x10^(-3)
⇒ -y = 2.89x10^(-3) - 4.55x10^(-3)
⇒ y = 4.55x10^(-3) - 2.89x10^(-3)
⇒ y = 1.66x10^(-3) moles
No. of molecules in 1 mole = 6.022x10^(23)
No. of molecules in y moles = yx6.022x10^(23) = 1.66x10^(-3)x6.022x10^(23)
=9.97x10^(20)
=9.97x10^(20)
Thus x = 9.97x10^(20) molecules
This question is part of UPSC exam. View all NEET courses
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If x molecules are removed from 200mg N2O?
Question is;If X molecules are removed from 200 mg N2O 2.89×10-3 moles of N2O are left. Then x will be.
Community Answer
If x molecules are removed from 200mg N2O?
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If x molecules are removed from 200mg N2O? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If x molecules are removed from 200mg N2O? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If x molecules are removed from 200mg N2O?.
If x molecules are removed from 200mg N2O? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If x molecules are removed from 200mg N2O? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If x molecules are removed from 200mg N2O?.
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