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A quantity of 1.878g of a metal bromide when heated in a stream of hydrogen chloride gas is completely converted to the chloride weighing 1g. The specific heat of the metal is 0.14. What is the molecular weight of the bromide? (Br= 80, Cl=35.5) a) 45.54 b) 125.54 c) 285.55 d) 205.54?
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A quantity of 1.878g of a metal bromide when heated in a stream of hyd...
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A quantity of 1.878g of a metal bromide when heated in a stream of hyd...
Explanation:
To solve this problem, we need to use the law of conservation of mass, which states that the mass of the reactants equals the mass of the products in a chemical reaction.
Step 1: Write the chemical equation for the reaction between the metal bromide and hydrogen chloride gas:
Metal bromide + Hydrogen chloride gas → Metal chloride + Hydrogen gas
The equation tells us that one mole of the metal bromide reacts with two moles of hydrogen chloride gas to produce one mole of the metal chloride and one mole of hydrogen gas.
Step 2: Calculate the number of moles of metal chloride produced:
Mass of metal chloride = 1g
Molar mass of metal chloride = Atomic mass of metal + Atomic mass of chlorine = x + 35.5
Number of moles of metal chloride = Mass of metal chloride / Molar mass of metal chloride
Number of moles of metal chloride = 1g / (x + 35.5) g/mol
Step 3: Calculate the number of moles of metal bromide used:
Mass of metal bromide = 1.878g
Molar mass of metal bromide = Atomic mass of metal + Atomic mass of bromine = x + 80
Number of moles of metal bromide = Mass of metal bromide / Molar mass of metal bromide
Number of moles of metal bromide = 1.878g / (x + 80) g/mol
Step 4: Use the law of conservation of mass to equate the number of moles of metal chloride produced to the number of moles of metal bromide used:
Number of moles of metal chloride = Number of moles of metal bromide
1g / (x + 35.5) g/mol = 1.878g / (x + 80) g/mol
Step 5: Solve for x to determine the molecular weight of the metal bromide:
1g(x + 80) = 1.878g(x + 35.5)
x = 125.54
Therefore, the molecular weight of the metal bromide is 125.54 g/mol, and the correct answer is (b) 125.54.
To solve this problem, we need to use the law of conservation of mass, which states that the mass of the reactants equals the mass of the products in a chemical reaction.
Step 1: Write the chemical equation for the reaction between the metal bromide and hydrogen chloride gas:
Metal bromide + Hydrogen chloride gas → Metal chloride + Hydrogen gas
The equation tells us that one mole of the metal bromide reacts with two moles of hydrogen chloride gas to produce one mole of the metal chloride and one mole of hydrogen gas.
Step 2: Calculate the number of moles of metal chloride produced:
Mass of metal chloride = 1g
Molar mass of metal chloride = Atomic mass of metal + Atomic mass of chlorine = x + 35.5
Number of moles of metal chloride = Mass of metal chloride / Molar mass of metal chloride
Number of moles of metal chloride = 1g / (x + 35.5) g/mol
Step 3: Calculate the number of moles of metal bromide used:
Mass of metal bromide = 1.878g
Molar mass of metal bromide = Atomic mass of metal + Atomic mass of bromine = x + 80
Number of moles of metal bromide = Mass of metal bromide / Molar mass of metal bromide
Number of moles of metal bromide = 1.878g / (x + 80) g/mol
Step 4: Use the law of conservation of mass to equate the number of moles of metal chloride produced to the number of moles of metal bromide used:
Number of moles of metal chloride = Number of moles of metal bromide
1g / (x + 35.5) g/mol = 1.878g / (x + 80) g/mol
Step 5: Solve for x to determine the molecular weight of the metal bromide:
1g(x + 80) = 1.878g(x + 35.5)
x = 125.54
Therefore, the molecular weight of the metal bromide is 125.54 g/mol, and the correct answer is (b) 125.54.
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A quantity of 1.878g of a metal bromide when heated in a stream of hydrogen chloride gas is completely converted to the chloride weighing 1g. The specific heat of the metal is 0.14. What is the molecular weight of the bromide? (Br= 80, Cl=35.5) a) 45.54 b) 125.54 c) 285.55 d) 205.54?
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A quantity of 1.878g of a metal bromide when heated in a stream of hydrogen chloride gas is completely converted to the chloride weighing 1g. The specific heat of the metal is 0.14. What is the molecular weight of the bromide? (Br= 80, Cl=35.5) a) 45.54 b) 125.54 c) 285.55 d) 205.54? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A quantity of 1.878g of a metal bromide when heated in a stream of hydrogen chloride gas is completely converted to the chloride weighing 1g. The specific heat of the metal is 0.14. What is the molecular weight of the bromide? (Br= 80, Cl=35.5) a) 45.54 b) 125.54 c) 285.55 d) 205.54? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A quantity of 1.878g of a metal bromide when heated in a stream of hydrogen chloride gas is completely converted to the chloride weighing 1g. The specific heat of the metal is 0.14. What is the molecular weight of the bromide? (Br= 80, Cl=35.5) a) 45.54 b) 125.54 c) 285.55 d) 205.54?.
A quantity of 1.878g of a metal bromide when heated in a stream of hydrogen chloride gas is completely converted to the chloride weighing 1g. The specific heat of the metal is 0.14. What is the molecular weight of the bromide? (Br= 80, Cl=35.5) a) 45.54 b) 125.54 c) 285.55 d) 205.54? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A quantity of 1.878g of a metal bromide when heated in a stream of hydrogen chloride gas is completely converted to the chloride weighing 1g. The specific heat of the metal is 0.14. What is the molecular weight of the bromide? (Br= 80, Cl=35.5) a) 45.54 b) 125.54 c) 285.55 d) 205.54? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A quantity of 1.878g of a metal bromide when heated in a stream of hydrogen chloride gas is completely converted to the chloride weighing 1g. The specific heat of the metal is 0.14. What is the molecular weight of the bromide? (Br= 80, Cl=35.5) a) 45.54 b) 125.54 c) 285.55 d) 205.54?.
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