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Sides AB and AC of median AD of triangle ABC are proportional to sides PQ and PR and median PM of another triangle PQR . show ABC similar to PQR?
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Sides AB and AC of median AD of triangle ABC are proportional to sides...
Given: Two triangles ΔABC and ΔPQR in which AD and PM are medians such that AB/PQ = AC/PR = AD/PM

To Prove: ΔABC ~ ΔPQR

Construction: Produce AD to E so that AD = DE. Join CE, Similarly produce PM to N such that PM = MN, also Join RN.

Proof: In ΔABD and ΔCDE, we have

AD = DE  [By Construction]

BD = DC [∴ AP is the median]

and, ∠ADB = ∠CDE [Vertically opp. angles]

∴ ΔABD ≅ ΔCDE [By SAS criterion of congruence]

⇒ AB = CE [CPCT] ...(i)

Also, in ΔPQM and ΔMNR, we have

PM = MN [By Construction]

QM = MR [∴ PM is the median]

and, ∠PMQ = ∠NMR [Vertically opposite angles]

∴ ΔPQM = ΔMNR [By SAS criterion of congruence]

⇒ PQ = RN [CPCT] ...(ii)

Now, AB/PQ = AC/PR = AD/PM

⇒ CE/RN = AC/PR = AD/PM ...[From (i) and(ii)]

⇒ CE/RN = AC/PR = 2AD/2PM

⇒ CE/RN = AC/PR = AE/PN [∴ 2AD = AE and 2PM = PN]

∴ ΔACE ~ ΔPRN [By SSS similarity criterion]

Therefore, ∠2 = ∠4

Similarly, ∠1 = ∠3

∴ ∠1 + ∠2 = ∠3 + ∠4

⇒ ∠A = ∠P ...(iii)

Now, In ΔABC and ΔPQR, we have

AB/PQ = AC/PR (Given)

∠A = ∠P [From (iii)]

∴ ΔABC ~ ΔPQR [By SAS similarity criterion]
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Most Upvoted Answer
Sides AB and AC of median AD of triangle ABC are proportional to sides...
Proof of Triangle Similarity
- Given Information:
- In triangle ABC, sides AB and AC of median AD are proportional to sides PQ and PR of triangle PQR.
- Median PM of triangle PQR is also proportional to sides AB and AC of triangle ABC.
- To Prove:
- Triangle ABC is similar to triangle PQR.
- Proof:
- Let's denote the lengths of the sides as follows:
- AB = k1 * PQ
- AC = k2 * PR
- PM = k3 * AB
- Since AD is a median of triangle ABC, we know that AD = (AB + AC)/2.
- Substituting the values of AB and AC, we get AD = (k1 * PQ + k2 * PR)/2.
- Similarly, since PM is a median of triangle PQR, PM = (PQ + PR)/2.
- From the given information, we have PM = k3 * AB. Substituting the value of AB, we get PM = k3 * k1 * PQ.
- Conclusion:
- By comparing the ratios of the sides and medians of the two triangles, we can see that the triangles are similar by SSS (Side-Side-Side) similarity criterion.
- Therefore, triangle ABC is similar to triangle PQR.
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