Two bodies A and B of same emissivity are placed in an evacuated vesse...
To= 27+273= 300
Ta=320+273=593
Tb=127+273=400
The rate of heat loss is directly proportional to the
Ea/Eb=(Ta^4 - To^4) / (Tb - To^4).
Two bodies A and B of same emissivity are placed in an evacuated vesse...
Explanation of Heat Loss Ratio:
- The rate of heat loss from a body is given by the formula: Q = εσA(T^4 - T0^4), where ε is the emissivity, σ is the Stefan-Boltzmann constant, A is the surface area, T is the temperature of the body, and T0 is the temperature of the surroundings.
Calculating Heat Loss from Body A:
- Let's assume the surface area of both bodies A and B is the same.
- Temperature of body A (T_A) = 320 C
- Temperature of surroundings (T0) = 27 C
- According to the formula, Q_A = εσA(T_A^4 - T0^4)
Calculating Heat Loss from Body B:
- Temperature of body B (T_B) = 127 C
- According to the formula, Q_B = εσA(T_B^4 - T0^4)
Ratio of Heat Loss:
- Now, to find the ratio of heat loss from bodies A and B, we can calculate Q_A/Q_B.
- Substitute the values of Q_A and Q_B in the ratio.
Conclusion:
- The ratio of the rates of heat loss from bodies A and B will be nearly in the ratio of (320^4 - 27^4) : (127^4 - 27^4).
- This ratio will give us an understanding of how the temperatures of the bodies affect the rate of heat loss, considering they have the same emissivity and surface area.
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