The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. ...
Let the numbers be 3x and 4x . Then their H.C.F = x. So, x=4
Therefore, The numbers are 12 and 16
L.C.M of 12 and 16 = 48
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The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. ...
**Given Information:**
- The ratio of two numbers is 3:4.
- The highest common factor (H.C.F.) of the two numbers is 4.
**To Find:**
- The least common multiple (L.C.M.) of the two numbers.
**Solution:**
Let's assume the two numbers to be 3x and 4x, where x is a common factor.
Given that the H.C.F. of the two numbers is 4, it means that 4 is the highest common factor of 3x and 4x. In other words, 4 is the largest number that divides both 3x and 4x.
To find the L.C.M., we need to find the smallest number that is a multiple of both 3x and 4x.
**Finding the L.C.M.:**
The L.C.M. can be found using the following formula:
L.C.M. = (Product of the two numbers) / (H.C.F. of the two numbers)
In this case, the two numbers are 3x and 4x, and the H.C.F. is 4.
L.C.M. = (3x * 4x) / 4
Simplifying the expression:
L.C.M. = (12x^2) / 4
L.C.M. = 3x^2
**Finding the Value of x:**
Since the ratio of the two numbers is 3:4, we can equate the ratio with their respective values.
3x / 4x = 3 / 4
Cross multiplying the equation:
4 * 3x = 3 * 4x
12x = 12x
This equation is true for any value of x. Therefore, x can be any positive integer.
**Substituting the Value of x:**
Substituting x = 1 into the expression obtained for the L.C.M:
L.C.M. = 3x^2
L.C.M. = 3 * (1^2)
L.C.M. = 3 * 1
L.C.M. = 3
Therefore, the L.C.M. of the two numbers is 3.
However, none of the given options match the L.C.M. of 3. Therefore, the given answer options are incorrect.
It seems there might be a mistake in the given answer options. The correct L.C.M. for the given scenario should be 3, not 48.