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If 0.3 moles of nitrogen gas n some Helium is mixed in a vessel in a 1/4 ratio by moles then total pressure exerted was 3atm if temperature is 300K then volume of Nitrogen gas will be?
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If 0.3 moles of nitrogen gas n some Helium is mixed in a vessel in a 1...
Given:
- Moles of nitrogen gas = 0.3
- Ratio of nitrogen gas to helium = 1:4
- Total pressure exerted = 3 atm
- Temperature = 300 K
To find:
- Volume of nitrogen gas
Solution:
Step 1: Calculate the moles of helium
- Since the ratio of nitrogen gas to helium is 1:4, the moles of helium can be calculated as follows:
Moles of helium = 4 * Moles of nitrogen gas = 4 * 0.3 = 1.2
Step 2: Calculate the total moles of gas
- Total moles of gas = Moles of nitrogen gas + Moles of helium = 0.3 + 1.2 = 1.5
Step 3: Apply the ideal gas law to calculate the volume of nitrogen gas
- The ideal gas law is given by PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
- Rearranging the equation, we get V = (nRT) / P
Step 4: Substitute the given values into the equation
- R is the gas constant and has a value of 0.0821 L·atm/(mol·K)
- Substituting the given values, we get V = (0.3 * 0.0821 * 300) / 3
Step 5: Calculate the volume of nitrogen gas
- V = (0.3 * 0.0821 * 300) / 3 = 7.843 L
Therefore, the volume of nitrogen gas in the mixture is 7.843 L.
- Moles of nitrogen gas = 0.3
- Ratio of nitrogen gas to helium = 1:4
- Total pressure exerted = 3 atm
- Temperature = 300 K
To find:
- Volume of nitrogen gas
Solution:
Step 1: Calculate the moles of helium
- Since the ratio of nitrogen gas to helium is 1:4, the moles of helium can be calculated as follows:
Moles of helium = 4 * Moles of nitrogen gas = 4 * 0.3 = 1.2
Step 2: Calculate the total moles of gas
- Total moles of gas = Moles of nitrogen gas + Moles of helium = 0.3 + 1.2 = 1.5
Step 3: Apply the ideal gas law to calculate the volume of nitrogen gas
- The ideal gas law is given by PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
- Rearranging the equation, we get V = (nRT) / P
Step 4: Substitute the given values into the equation
- R is the gas constant and has a value of 0.0821 L·atm/(mol·K)
- Substituting the given values, we get V = (0.3 * 0.0821 * 300) / 3
Step 5: Calculate the volume of nitrogen gas
- V = (0.3 * 0.0821 * 300) / 3 = 7.843 L
Therefore, the volume of nitrogen gas in the mixture is 7.843 L.
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If 0.3 moles of nitrogen gas n some Helium is mixed in a vessel in a 1...
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If 0.3 moles of nitrogen gas n some Helium is mixed in a vessel in a 1/4 ratio by moles then total pressure exerted was 3atm if temperature is 300K then volume of Nitrogen gas will be?
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If 0.3 moles of nitrogen gas n some Helium is mixed in a vessel in a 1/4 ratio by moles then total pressure exerted was 3atm if temperature is 300K then volume of Nitrogen gas will be? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If 0.3 moles of nitrogen gas n some Helium is mixed in a vessel in a 1/4 ratio by moles then total pressure exerted was 3atm if temperature is 300K then volume of Nitrogen gas will be? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 0.3 moles of nitrogen gas n some Helium is mixed in a vessel in a 1/4 ratio by moles then total pressure exerted was 3atm if temperature is 300K then volume of Nitrogen gas will be?.
If 0.3 moles of nitrogen gas n some Helium is mixed in a vessel in a 1/4 ratio by moles then total pressure exerted was 3atm if temperature is 300K then volume of Nitrogen gas will be? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If 0.3 moles of nitrogen gas n some Helium is mixed in a vessel in a 1/4 ratio by moles then total pressure exerted was 3atm if temperature is 300K then volume of Nitrogen gas will be? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 0.3 moles of nitrogen gas n some Helium is mixed in a vessel in a 1/4 ratio by moles then total pressure exerted was 3atm if temperature is 300K then volume of Nitrogen gas will be?.
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