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Two trains are moving in opposite directions with speed of 60 km/hr and 90 km/hr respectively. Their lengths are 1.10 km and 0.9 km respectively. the slower train cross the faster train in --- seconds
- a)56
- b)48
- c)47
- d)26
Correct answer is option 'B'. Can you explain this answer?
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Two trains are moving in opposite directions with speed of 60 km/hr an...
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Two trains are moving in opposite directions with speed of 60 km/hr an...
Given:
- Speed of the slower train = 60 km/hr
- Speed of the faster train = 90 km/hr
- Length of the slower train = 1.10 km
- Length of the faster train = 0.9 km
To Find:
- Time taken for the slower train to cross the faster train
Approach:
- When two trains are moving in opposite directions, the total distance to be covered by the slower train to cross the faster train is equal to the sum of their lengths.
- The relative speed between the two trains is the sum of their speeds.
- Using the formula: Time = Distance/Speed, we can find the time taken for the slower train to cross the faster train.
Calculation:
- Total distance to be covered by the slower train = Length of slower train + Length of faster train = 1.10 km + 0.9 km = 2 km
- Relative speed between the two trains = Speed of slower train + Speed of faster train = 60 km/hr + 90 km/hr = 150 km/hr
- Time taken = Distance/Speed = 2 km / 150 km/hr
Conversion:
- Convert km/hr to m/s by multiplying with 5/18 (1 km/hr = 5/18 m/s)
- Time taken = 2 km * (5/18 m/s) / (150 km/hr * (5/18 m/s))
Simplification:
- Time taken = 2000 m / (150 * 5) s
- Time taken = 8 s
Answer:
The slower train crosses the faster train in 8 seconds.
- Speed of the slower train = 60 km/hr
- Speed of the faster train = 90 km/hr
- Length of the slower train = 1.10 km
- Length of the faster train = 0.9 km
To Find:
- Time taken for the slower train to cross the faster train
Approach:
- When two trains are moving in opposite directions, the total distance to be covered by the slower train to cross the faster train is equal to the sum of their lengths.
- The relative speed between the two trains is the sum of their speeds.
- Using the formula: Time = Distance/Speed, we can find the time taken for the slower train to cross the faster train.
Calculation:
- Total distance to be covered by the slower train = Length of slower train + Length of faster train = 1.10 km + 0.9 km = 2 km
- Relative speed between the two trains = Speed of slower train + Speed of faster train = 60 km/hr + 90 km/hr = 150 km/hr
- Time taken = Distance/Speed = 2 km / 150 km/hr
Conversion:
- Convert km/hr to m/s by multiplying with 5/18 (1 km/hr = 5/18 m/s)
- Time taken = 2 km * (5/18 m/s) / (150 km/hr * (5/18 m/s))
Simplification:
- Time taken = 2000 m / (150 * 5) s
- Time taken = 8 s
Answer:
The slower train crosses the faster train in 8 seconds.
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Two trains are moving in opposite directions with speed of 60 km/hr and 90 km/hr respectively. Their lengths are 1.10 km and 0.9 km respectively. the slower train cross the faster train in --- secondsa)56b)48c)47d)26Correct answer is option 'B'. Can you explain this answer?
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