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Two trains, each 100 m long are moving in opposite directions. They cross each other in 8 seconds. If one is moving twice as fast the other, the speed of the faster train is
  • a)
    75 km/hr
  • b)
    60 km/hr
  • c)
    35 km/hr
  • d)
    70 km/hr
Correct answer is option 'B'. Can you explain this answer?
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Two trains, each 100 m long are moving in opposite directions. They cr...
Solution:

Given, length of each train = 100 m
Time taken to cross each other = 8 sec

Let the speed of the slower train be x m/s
Then, the speed of the faster train = 2x m/s

Relative speed of the trains = (speed of slower train + speed of faster train)
= (x + 2x) m/s
= 3x m/s

Distance covered during crossing = sum of the lengths of the trains = 100 + 100 = 200 m

Using the formula, distance = speed × time
we can find the speed of slower train as follows:

distance = speed × time
=> 200 = 3x × 8
=> x = 6.25 m/s

Converting the speed to km/hr, we get:

Speed of slower train = 6.25 × 18/5 km/hr
= 22.5 km/hr

Speed of faster train = 2x = 2 × 6.25 m/s = 12.5 m/s

Converting the speed to km/hr, we get:

Speed of faster train = 12.5 × 18/5 km/hr
= 45 km/hr

Therefore, the speed of the faster train is 45 km/hr, which is option B.
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Two trains, each 100 m long are moving in opposite directions. They cross each other in 8 seconds. If one is moving twice as fast the other, the speed of the faster train is a)75 km/hrb)60 km/hrc)35 km/hr d)70 km/hrCorrect answer is option 'B'. Can you explain this answer?
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