A body starts from rest with uniform acceleration.If its velocity afte...
A body starts from rest with uniform acceleration.If its velocity afte...
Problem Analysis:
The given problem can be solved using the equations of motion under uniform acceleration. We are given that the body starts from rest, so the initial velocity (u) is 0. The velocity after 'n' seconds (v) is also given. We need to find the displacement in the last two seconds.
Solution:
To find the displacement, we can use the equation of motion: v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken.
Since the body starts from rest, the initial velocity (u) is 0. Therefore, the equation simplifies to v = at.
Given that the velocity after 'n' seconds is 'v', we can write v = a*n. Solving for acceleration, we get a = v/n.
To find the displacement in the last two seconds, we can use the equation of motion: s = ut + (1/2)at^2, where s is the displacement.
Substituting the values, we have s = 0*t + (1/2)*(v/n)*t^2. Simplifying further, s = (v/n)*(t^2)/2.
Since we need to find the displacement in the last two seconds, we substitute t = n - 2 in the equation. Therefore, s = (v/n)*((n - 2)^2)/2.
Simplifying the expression, we get s = (v/n)*((n^2 - 4n + 4))/2. Further simplification gives s = (v(n - 2))/n.
Therefore, the displacement in the last two seconds is given by the expression s = (v(n - 2))/n.
Answer:
The correct answer is option 3) v(n-1)/n.
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