If 100 ml of 1N H2SO4 is mixed with 100ml of 1M NaOH soln.The resultin...
Solution:
The reaction between H2SO4 and NaOH can be represented as:
H2SO4 + 2NaOH → Na2SO4 + 2H2O
From the balanced equation, we can see that one mole of H2SO4 reacts with two moles of NaOH.
Given, the concentration of H2SO4 is 1N, which means that it contains 1 mole of H2SO4 per liter of solution. Therefore, the number of moles of H2SO4 in 100 ml of 1N H2SO4 solution can be calculated as:
Number of moles of H2SO4 = (1N × 100 ml) / 1000 ml = 0.1 moles
Similarly, the concentration of NaOH is 1M, which means that it contains 1 mole of NaOH per liter of solution. Therefore, the number of moles of NaOH in 100 ml of 1M NaOH solution can be calculated as:
Number of moles of NaOH = (1M × 100 ml) / 1000 ml = 0.1 moles
Since the reaction between H2SO4 and NaOH is a neutralization reaction, the number of moles of H2SO4 should be equal to the number of moles of NaOH for complete neutralization.
In this case, the number of moles of H2SO4 is 0.1 moles and the number of moles of NaOH is also 0.1 moles. Therefore, the two solutions will completely neutralize each other, resulting in a neutral solution.
Hence, the answer is (b) Neutral.
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Solution:
- Reaction between H2SO4 and NaOH: H2SO4 + 2NaOH → Na2SO4 + 2H2O
- H2SO4 concentration = 1N, moles of H2SO4 in 100 ml = 0.1 moles
- NaOH concentration = 1M, moles of NaOH in 100 ml = 0.1 moles
- For neutralization, moles of H2SO4 = moles of NaOH = 0.1 moles
- Since moles are equal, the resulting solution will be neutral
- Answer: (b) Neutral