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A source of sound has a noise level of 20 dB. If the intensity of sound produced by the source increases by 100 times, the noise level becomes
- a)30 dB
- b)40 dB
- c)400 dB
- d)20,000 dB
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A source of sound has a noise level of 20 dB. If the intensity of soun...
∵ β = 10 log(I/I0)
∴ β2 - β1 = 10 log(I2/I1)
⇒ x - 20 = 10 log(100/1) [∵ β1 = 20dB]
x - 20 = 10 log100
x - 20 = 10 log102
x - 20 = 20 log10
x - 20 = 20 [∵ log10 = 1]
x = 40dB
∴ β2 - β1 = 10 log(I2/I1)
⇒ x - 20 = 10 log(100/1) [∵ β1 = 20dB]
x - 20 = 10 log100
x - 20 = 10 log102
x - 20 = 20 log10
x - 20 = 20 [∵ log10 = 1]
x = 40dB
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A source of sound has a noise level of 20 dB. If the intensity of soun...
Explanation:
Definition: Noise level is defined as the logarithmic measure of the ratio of the sound pressure level to the reference sound pressure level which is 20 micro Pascals.
Formula:
Noise level (dB) = 10 log10 [I/I0]
Where, I is the intensity of sound and I0 is the reference intensity of sound which is 10^-12 W/m^2.
Given,
Noise level = 20 dB
Intensity of sound produced by the source increases by 100 times.
Let us calculate the new noise level:
New intensity of sound = 100 x I0 = 100 x 10^-12 W/m^2 = 10^-10 W/m^2
New noise level (dB) = 10 log10 [(10^-10) / (10^-12)]
New noise level (dB) = 10 log10 (10^2) = 10 x 2 = 20 + 20 = 40 dB
Hence, the new noise level becomes 40 dB when the intensity of sound produced by the source increases by 100 times.
Answer:
Option (b) is the correct answer.
Definition: Noise level is defined as the logarithmic measure of the ratio of the sound pressure level to the reference sound pressure level which is 20 micro Pascals.
Formula:
Noise level (dB) = 10 log10 [I/I0]
Where, I is the intensity of sound and I0 is the reference intensity of sound which is 10^-12 W/m^2.
Given,
Noise level = 20 dB
Intensity of sound produced by the source increases by 100 times.
Let us calculate the new noise level:
New intensity of sound = 100 x I0 = 100 x 10^-12 W/m^2 = 10^-10 W/m^2
New noise level (dB) = 10 log10 [(10^-10) / (10^-12)]
New noise level (dB) = 10 log10 (10^2) = 10 x 2 = 20 + 20 = 40 dB
Hence, the new noise level becomes 40 dB when the intensity of sound produced by the source increases by 100 times.
Answer:
Option (b) is the correct answer.
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A source of sound has a noise level of 20 dB. If the intensity of sound produced by the source increases by 100 times, the noise level becomesa) 30 dB b) 40 dB c) 400 dB d) 20,000 dB Correct answer is option 'B'. Can you explain this answer?
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