An electron in an atom jumps in such a way that it's KE changes from x...
The change in kinetic energy [KE]:-
x - x/4 = + 3x/4
Since KE = modulus of TE
Therefore TE = 3x/4
PE [Potential energy] = 2 TE
PE = 2 * 3x/4
PE = + 3x/2.
So all the given options are wrong.
An electron in an atom jumps in such a way that it's KE changes from x...
Problem:
An electron in an atom jumps in such a way that it's KE changes from x to x/4. The change in PE is
a) 3/4x
b) -3/8x
c) 3/4x
d) -3/4x
Solution:
To solve the problem, we need to use the conservation of energy principle. The total energy of the system (electron and atom) must remain constant. Therefore, the change in KE must be balanced by a change in PE.
Let the initial kinetic energy of the electron be KE1 = x, and the final kinetic energy be KE2 = x/4.
Step 1: Find the change in KE:
ΔKE = KE2 - KE1 = x/4 - x = -3x/4
Step 2: Find the change in PE:
ΔPE = -ΔKE = 3x/4
Therefore, the answer is (c) 3/4x.
Explanation:
The change in KE is negative, which means the electron lost energy. This energy must have been transferred to the atom in the form of a gain in potential energy. The change in PE is positive, which means the electron moved to a higher energy level farther from the nucleus.
Using the conservation of energy principle, we can conclude that the electron made a transition to a higher energy level, which required energy to be supplied to the electron. The energy required to make this transition was exactly equal to the change in PE, which is 3/4x.
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