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What is the frequency of revolution of electron present in 2nd Bohr's orbit of H atom? a) 1.016×10^16 b) 4.065×10^16 c) 1.626×10^15 d) 8.2×10^14?
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Frequency of Revolution of Electron in 2nd Bohr's Orbit of H Atom
Bohr's model of an atom states that the electrons revolve around the nucleus in certain fixed orbits. The frequency of revolution of an electron can be calculated using the formula:
f = (Z^2 * v) / (n^2 * h)
Where,
Z = atomic number of the element
v = velocity of the electron
n = principal quantum number of the orbit
h = Planck's constant
For hydrogen atom, Z = 1 and n = 2 (as we are considering the 2nd Bohr's orbit). The velocity of the electron can be calculated using the formula:
v = (Ze^2) / (4πε_0rn)
Where,
e = charge on an electron
ε_0 = permittivity of free space
r = radius of the orbit
n = principal quantum number of the orbit
Substituting the values in the above formulas, we get:
v = 2.19 × 10^6 m/s
f = 1.626 × 10^15 Hz
Therefore, the correct option is c) 1.626 × 10^15.
Explanation:
- Bohr's model of an atom
- Formula to calculate frequency of revolution of an electron
- Calculation of velocity of the electron using the formula
- Substituting the values in the formula to calculate the frequency
- Final answer
Bohr's model of an atom states that the electrons revolve around the nucleus in certain fixed orbits. The frequency of revolution of an electron can be calculated using the formula:
f = (Z^2 * v) / (n^2 * h)
Where,
Z = atomic number of the element
v = velocity of the electron
n = principal quantum number of the orbit
h = Planck's constant
For hydrogen atom, Z = 1 and n = 2 (as we are considering the 2nd Bohr's orbit). The velocity of the electron can be calculated using the formula:
v = (Ze^2) / (4πε_0rn)
Where,
e = charge on an electron
ε_0 = permittivity of free space
r = radius of the orbit
n = principal quantum number of the orbit
Substituting the values in the above formulas, we get:
v = 2.19 × 10^6 m/s
f = 1.626 × 10^15 Hz
Therefore, the correct option is c) 1.626 × 10^15.
Explanation:
- Bohr's model of an atom
- Formula to calculate frequency of revolution of an electron
- Calculation of velocity of the electron using the formula
- Substituting the values in the formula to calculate the frequency
- Final answer
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What is the frequency of revolution of electron present in 2nd Bohr's orbit of H atom? a) 1.016×10^16 b) 4.065×10^16 c) 1.626×10^15 d) 8.2×10^14?
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What is the frequency of revolution of electron present in 2nd Bohr's orbit of H atom? a) 1.016×10^16 b) 4.065×10^16 c) 1.626×10^15 d) 8.2×10^14? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about What is the frequency of revolution of electron present in 2nd Bohr's orbit of H atom? a) 1.016×10^16 b) 4.065×10^16 c) 1.626×10^15 d) 8.2×10^14? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the frequency of revolution of electron present in 2nd Bohr's orbit of H atom? a) 1.016×10^16 b) 4.065×10^16 c) 1.626×10^15 d) 8.2×10^14?.
What is the frequency of revolution of electron present in 2nd Bohr's orbit of H atom? a) 1.016×10^16 b) 4.065×10^16 c) 1.626×10^15 d) 8.2×10^14? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about What is the frequency of revolution of electron present in 2nd Bohr's orbit of H atom? a) 1.016×10^16 b) 4.065×10^16 c) 1.626×10^15 d) 8.2×10^14? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the frequency of revolution of electron present in 2nd Bohr's orbit of H atom? a) 1.016×10^16 b) 4.065×10^16 c) 1.626×10^15 d) 8.2×10^14?.
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