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A, B, C, D and E are five consecutive integers and the average of these five numbers is less than 1/4 th of A.Then A is
  • a)
    Positive
  • b)
    Negative
  • c)
    Even
  • d)
    Data Sufficient
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A, B, C, D and E are five consecutive integers and the average of thes...
To solve this problem, let's first understand the given information:

1. A, B, C, D, and E are five consecutive integers. This means that the numbers are in the order A, A+1, A+2, A+3, and A+4.
2. The average of these five numbers is less than 1/4th of A. This can be expressed as (A + A+1 + A+2 + A+3 + A+4)/5 < />

Now, let's solve the problem step by step:

Step 1: Simplify the average inequality equation
(A + A+1 + A+2 + A+3 + A+4)/5 < />
(5A + 10)/5 < />
5A + 10 < />

Step 2: Multiply both sides by 4 to eliminate the fraction
4(5A + 10) < />
20A + 40 < />

Step 3: Simplify the equation
20A + 40 < />
15A < />
A < />
A < />

Step 4: Analyze the value of A
Since A is an integer (as given in the problem), the value of A cannot be a fraction. Therefore, A must be a negative integer.

Step 5: Conclusion
Based on the analysis above, we can conclude that A must be negative.

Therefore, the correct answer is option 'A' - Negative.
Community Answer
A, B, C, D and E are five consecutive integers and the average of thes...
Let five consecutive integers , A= n , B = n + 1 , C = n + 2 , D = n + 3 , E = n + 4 Since , n + n + 1+ n + 2 + n+ 3 + n + 4 /5 < n/4="" 5n="" +="" 10="" 5="" />< n/4="" n="" +="" 2="" />< n="" 2="" />< n/4="" -="" n="" 2="" />< -3n="" 8="" />< -="" 3n="" -8/3="" />< n="" n="" /> -8/3 n is great -8/3 So, n is positive Therefore , n is equal to A Hence , A is positive .
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A, B, C, D and E are five consecutive integers and the average of these five numbers is less than 1/4 th of A.Then A isa)Positiveb)Negativec)Evend)Data SufficientCorrect answer is option 'A'. Can you explain this answer?
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