AOBC is a rectangle whose three vertices are A(0,3) O(0,0)and B(5,0 ) Find the length of its diagonal?

Question

Answer

On plotting the line for making a rectangle with these coordinate points we get a rectangle whose length = (5 unit) long and breadth = (3 unit) broad.

Hence for calculating diagonal of rectangle using Pythagoras we have altitude = 3unit. and base = 5 unit

=} diagonal = √5^2 + 3^2
=} √ 25+9
=}√34 unit

That's all

Answer

Answer

Finding the Length of the Diagonal of Rectangle AOBC

Given Points:
- A(0,3)
- O(0,0)
- B(5,0)

Formula for Finding the Length of the Diagonal of a Rectangle:
- The length of the diagonal of a rectangle can be found using the Pythagorean theorem.
- The formula is: diagonal length = √(length^2 + width^2)

Finding the Length of AO:
- The length of AO can be found using the distance formula: distance = √((x2 - x1)^2 + (y2 - y1)^2)
- AO = √((0-0)^2 + (3-0)^2) = √(0 + 9) = √9 = 3

Finding the Length of OB:
- The length of OB can be found using the distance formula: OB = √((5-0)^2 + (0-0)^2) = √(25 + 0) = √25 = 5

Calculating the Length of the Diagonal:
- Now, we have the length of AO as 3 and OB as 5.
- Using the Pythagorean theorem, diagonal length = √(3^2 + 5^2) = √(9 + 25) = √34

Therefore, the length of the diagonal of rectangle AOBC is √34 units.

Answer

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