Which of the following pairs of molecules have the almost equal bond d...
Bond dissociation enthalpy (BDE) is the energy required to break a particular bond in a molecule. The BDE values of different molecules can be compared to determine which pairs have similar bond strengths.
a) F2 and H2
- The bond dissociation enthalpy of F2 is 158 kJ/mol.
- The bond dissociation enthalpy of H2 is 436 kJ/mol.
- Therefore, F2 and H2 do not have almost equal bond dissociation enthalpies.
b) N2 and CO
- The bond dissociation enthalpy of N2 is 945 kJ/mol.
- The bond dissociation enthalpy of CO is 1072 kJ/mol.
- Therefore, N2 and CO do not have almost equal bond dissociation enthalpies.
c) F2 and I2
- The bond dissociation enthalpy of F2 is 158 kJ/mol.
- The bond dissociation enthalpy of I2 is 151 kJ/mol.
- Therefore, F2 and I2 have almost equal bond dissociation enthalpies.
d) O2 and HF
- The bond dissociation enthalpy of O2 is 498 kJ/mol.
- The bond dissociation enthalpy of HF is 568 kJ/mol.
- Therefore, O2 and HF do not have almost equal bond dissociation enthalpies.
In conclusion, the pair of molecules with almost equal bond dissociation enthalpies is F2 and I2.
Which of the following pairs of molecules have the almost equal bond d...
I think both b and c correct. N2 and CO have same bond order so they have almost equal bond dissociation enthalpy. And in case of F2 and I2, F2 has lone pair lone pair repulsion because of small size and I2 has low electronegativity. So their bond dissociation enthalpy almost same.
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