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A long straight wire carrying a current of 30A is placed in an external uniform magnetic field of induction 4 × 10-⁴ T the magnetic field is acting parallel to the direction of the current . the magnitude of the resultant magnetic induction in Tesla at a point 2cm away from the wire is?
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Calculating the Resultant Magnetic Induction
To calculate the resultant magnetic induction at a point 2cm away from the wire carrying a current of 30A in an external uniform magnetic field of induction 4 × 10^-4 T, we can use the superposition principle, which states that the total magnetic field at a point is the vector sum of the fields produced by each individual source separately.
Magnetic Field Due to the Current-Carrying Wire
- The magnetic field produced by a current-carrying wire is given by the formula B = (μ₀ * I) / (2π * r), where B is the magnetic field, μ₀ is the permeability of free space, I is the current, and r is the distance from the wire.
- Substituting the given values, we get B = (4π × 10^-7 * 30) / (2π * 0.02) = 6 × 10^-4 T
Magnetic Field Due to the External Magnetic Field
- The external uniform magnetic field is given as 4 × 10^-4 T, acting parallel to the direction of the current.
Resultant Magnetic Induction
- Since the external magnetic field and the magnetic field due to the current-carrying wire are parallel, the resultant magnetic induction is the sum of the two fields, B_total = B_wire + B_external.
- Therefore, B_total = 6 × 10^-4 T + 4 × 10^-4 T = 10 × 10^-4 T = 1 × 10^-3 T
Therefore, the magnitude of the resultant magnetic induction at a point 2cm away from the wire is 1 × 10^-3 Tesla.
To calculate the resultant magnetic induction at a point 2cm away from the wire carrying a current of 30A in an external uniform magnetic field of induction 4 × 10^-4 T, we can use the superposition principle, which states that the total magnetic field at a point is the vector sum of the fields produced by each individual source separately.
Magnetic Field Due to the Current-Carrying Wire
- The magnetic field produced by a current-carrying wire is given by the formula B = (μ₀ * I) / (2π * r), where B is the magnetic field, μ₀ is the permeability of free space, I is the current, and r is the distance from the wire.
- Substituting the given values, we get B = (4π × 10^-7 * 30) / (2π * 0.02) = 6 × 10^-4 T
Magnetic Field Due to the External Magnetic Field
- The external uniform magnetic field is given as 4 × 10^-4 T, acting parallel to the direction of the current.
Resultant Magnetic Induction
- Since the external magnetic field and the magnetic field due to the current-carrying wire are parallel, the resultant magnetic induction is the sum of the two fields, B_total = B_wire + B_external.
- Therefore, B_total = 6 × 10^-4 T + 4 × 10^-4 T = 10 × 10^-4 T = 1 × 10^-3 T
Therefore, the magnitude of the resultant magnetic induction at a point 2cm away from the wire is 1 × 10^-3 Tesla.
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A long straight wire carrying a current of 30A is placed in an external uniform magnetic field of induction 4 × 10-⁴ T the magnetic field is acting parallel to the direction of the current . the magnitude of the resultant magnetic induction in Tesla at a point 2cm away from the wire is?
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A long straight wire carrying a current of 30A is placed in an external uniform magnetic field of induction 4 × 10-⁴ T the magnetic field is acting parallel to the direction of the current . the magnitude of the resultant magnetic induction in Tesla at a point 2cm away from the wire is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A long straight wire carrying a current of 30A is placed in an external uniform magnetic field of induction 4 × 10-⁴ T the magnetic field is acting parallel to the direction of the current . the magnitude of the resultant magnetic induction in Tesla at a point 2cm away from the wire is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A long straight wire carrying a current of 30A is placed in an external uniform magnetic field of induction 4 × 10-⁴ T the magnetic field is acting parallel to the direction of the current . the magnitude of the resultant magnetic induction in Tesla at a point 2cm away from the wire is?.
A long straight wire carrying a current of 30A is placed in an external uniform magnetic field of induction 4 × 10-⁴ T the magnetic field is acting parallel to the direction of the current . the magnitude of the resultant magnetic induction in Tesla at a point 2cm away from the wire is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A long straight wire carrying a current of 30A is placed in an external uniform magnetic field of induction 4 × 10-⁴ T the magnetic field is acting parallel to the direction of the current . the magnitude of the resultant magnetic induction in Tesla at a point 2cm away from the wire is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A long straight wire carrying a current of 30A is placed in an external uniform magnetic field of induction 4 × 10-⁴ T the magnetic field is acting parallel to the direction of the current . the magnitude of the resultant magnetic induction in Tesla at a point 2cm away from the wire is?.
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