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A and B starts moving towards each other from two places 200 m apart. After walking 60 m, B turns left and goes 20 m, then he turns right and goes 40 m. He then turns right again and comes back to the road on which he had started walking. If A and B walk with the same speed, what is the distance between A and B now ?
- a)20 m
- b)30 m
- c)40 m
- d)50 m
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A and B starts moving towards each other from two places 200 m apart. ...
Clearly Y moves 60 m from Q upto A, then 20 m upto B, 40 m upto C and then upto D.
So, AD – BC = 40 m.
QD = (60 + 40) m = 100 m.
Since A and B travel with the name speed, A will travel the same speed along the horizontal as B travels in the same time. i.e. (60 + 20 + 40 + 20) = 140 m.
So. A travels 140m upto A.
Distance between A and B = AD – (100 – 60) m = 40 m.
Most Upvoted Answer
A and B starts moving towards each other from two places 200 m apart. ...
A coverage total 120 m.. and also B 120 mtr.,, but A is 80 mtr.. away from starting position of B and B is also 80mtr. from starting position of A. 80 +80. =160 200-160 =40 mgr between them
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Community Answer
A and B starts moving towards each other from two places 200 m apart. ...
Given:
Distance between A and B = 200 m
Distance covered by B before turning left = 60 m
Distance covered by B after turning left and then right and then right again = 20 m + 40 m + 20 m = 80 m
Let's assume that A and B meet at point C.
Distance covered by A = Distance covered by B
Distance covered by A before meeting B = 200 m - 60 m = 140 m
Let's assume that B's initial position was X and after coming back to the road, his final position is Y.
Distance from X to Y = Distance from Y to C (as B comes back to the same road he left from)
Let's assume that the distance from A to C is x.
So, the distance from B's initial position X to C is 140 m + x.
Now, we can apply Pythagoras theorem to find the distance between A and B.
Distance between A and B = √((140 + x)² + 80²)
To find the value of x, we can use the right triangle formed by A, C, and Y.
Distance from Y to C = Distance from A to C = x
Distance from X to Y = Distance from X to C - Distance from Y to C = (140 + x) - x = 140
Now, we can apply Pythagoras theorem again to find the value of x.
x² + 140² = (200 - 60)²
x² + 140² = 6400
x² = 6400 - 140²
x² = 33600
x = √33600
x = 183.11 m (approx.)
Substituting the value of x in the first equation, we get:
Distance between A and B = √((140 + 183.11)² + 80²)
Distance between A and B = √(323.11² + 6400)
Distance between A and B = √(104409.79)
Distance between A and B = 322.98 m (approx.)
Therefore, the distance between A and B now is 320 m (approx.), which is closest to option C.
Distance between A and B = 200 m
Distance covered by B before turning left = 60 m
Distance covered by B after turning left and then right and then right again = 20 m + 40 m + 20 m = 80 m
Let's assume that A and B meet at point C.
Distance covered by A = Distance covered by B
Distance covered by A before meeting B = 200 m - 60 m = 140 m
Let's assume that B's initial position was X and after coming back to the road, his final position is Y.
Distance from X to Y = Distance from Y to C (as B comes back to the same road he left from)
Let's assume that the distance from A to C is x.
So, the distance from B's initial position X to C is 140 m + x.
Now, we can apply Pythagoras theorem to find the distance between A and B.
Distance between A and B = √((140 + x)² + 80²)
To find the value of x, we can use the right triangle formed by A, C, and Y.
Distance from Y to C = Distance from A to C = x
Distance from X to Y = Distance from X to C - Distance from Y to C = (140 + x) - x = 140
Now, we can apply Pythagoras theorem again to find the value of x.
x² + 140² = (200 - 60)²
x² + 140² = 6400
x² = 6400 - 140²
x² = 33600
x = √33600
x = 183.11 m (approx.)
Substituting the value of x in the first equation, we get:
Distance between A and B = √((140 + 183.11)² + 80²)
Distance between A and B = √(323.11² + 6400)
Distance between A and B = √(104409.79)
Distance between A and B = 322.98 m (approx.)
Therefore, the distance between A and B now is 320 m (approx.), which is closest to option C.
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A and B starts moving towards each other from two places 200 m apart. After walking 60 m, B turns left and goes 20 m, then he turns right and goes 40 m. He then turns right again and comes back to the road on which he had started walking. If A and B walk with the same speed, what is the distance between A and B now ?a) 20 m b) 30 m c) 40 m d) 50 m Correct answer is option 'C'. Can you explain this answer?
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A and B starts moving towards each other from two places 200 m apart. After walking 60 m, B turns left and goes 20 m, then he turns right and goes 40 m. He then turns right again and comes back to the road on which he had started walking. If A and B walk with the same speed, what is the distance between A and B now ?a) 20 m b) 30 m c) 40 m d) 50 m Correct answer is option 'C'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about A and B starts moving towards each other from two places 200 m apart. After walking 60 m, B turns left and goes 20 m, then he turns right and goes 40 m. He then turns right again and comes back to the road on which he had started walking. If A and B walk with the same speed, what is the distance between A and B now ?a) 20 m b) 30 m c) 40 m d) 50 m Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A and B starts moving towards each other from two places 200 m apart. After walking 60 m, B turns left and goes 20 m, then he turns right and goes 40 m. He then turns right again and comes back to the road on which he had started walking. If A and B walk with the same speed, what is the distance between A and B now ?a) 20 m b) 30 m c) 40 m d) 50 m Correct answer is option 'C'. Can you explain this answer?.
A and B starts moving towards each other from two places 200 m apart. After walking 60 m, B turns left and goes 20 m, then he turns right and goes 40 m. He then turns right again and comes back to the road on which he had started walking. If A and B walk with the same speed, what is the distance between A and B now ?a) 20 m b) 30 m c) 40 m d) 50 m Correct answer is option 'C'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about A and B starts moving towards each other from two places 200 m apart. After walking 60 m, B turns left and goes 20 m, then he turns right and goes 40 m. He then turns right again and comes back to the road on which he had started walking. If A and B walk with the same speed, what is the distance between A and B now ?a) 20 m b) 30 m c) 40 m d) 50 m Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A and B starts moving towards each other from two places 200 m apart. After walking 60 m, B turns left and goes 20 m, then he turns right and goes 40 m. He then turns right again and comes back to the road on which he had started walking. If A and B walk with the same speed, what is the distance between A and B now ?a) 20 m b) 30 m c) 40 m d) 50 m Correct answer is option 'C'. Can you explain this answer?.
Solutions for A and B starts moving towards each other from two places 200 m apart. After walking 60 m, B turns left and goes 20 m, then he turns right and goes 40 m. He then turns right again and comes back to the road on which he had started walking. If A and B walk with the same speed, what is the distance between A and B now ?a) 20 m b) 30 m c) 40 m d) 50 m Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for SSC.
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A and B starts moving towards each other from two places 200 m apart. After walking 60 m, B turns left and goes 20 m, then he turns right and goes 40 m. He then turns right again and comes back to the road on which he had started walking. If A and B walk with the same speed, what is the distance between A and B now ?a) 20 m b) 30 m c) 40 m d) 50 m Correct answer is option 'C'. Can you explain this answer?, a detailed solution for A and B starts moving towards each other from two places 200 m apart. After walking 60 m, B turns left and goes 20 m, then he turns right and goes 40 m. He then turns right again and comes back to the road on which he had started walking. If A and B walk with the same speed, what is the distance between A and B now ?a) 20 m b) 30 m c) 40 m d) 50 m Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of A and B starts moving towards each other from two places 200 m apart. After walking 60 m, B turns left and goes 20 m, then he turns right and goes 40 m. He then turns right again and comes back to the road on which he had started walking. If A and B walk with the same speed, what is the distance between A and B now ?a) 20 m b) 30 m c) 40 m d) 50 m Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A and B starts moving towards each other from two places 200 m apart. After walking 60 m, B turns left and goes 20 m, then he turns right and goes 40 m. He then turns right again and comes back to the road on which he had started walking. If A and B walk with the same speed, what is the distance between A and B now ?a) 20 m b) 30 m c) 40 m d) 50 m Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice SSC tests.
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