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Plz anyone solve me this question.The dissociation cnstant of a weak acid HA and a weak base BOH are 2×10^-5 and 5×10^-6 respectively.The equilibrium constant for the neutralisation reaction of the two is(ignore hydrolysis of resulting salt)?
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Plz anyone solve me this question.The dissociation cnstant of a weak a...
Weak acid HA ,Ka=2 x 10-5 and weak base BOH, KB=5 x 10-6
Kh=Ka x Kb x Kh=Keq=Ka x Kb
Keq=(2 x 10-5)(5 x 10-6)
Keq=10 x 10-11
Keq=1 x 10-10
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Plz anyone solve me this question.The dissociation cnstant of a weak a...
To find the equilibrium constant for the neutralization reaction of a weak acid (HA) and a weak base (BOH), we can use the dissociation constants provided.
Step 1: Understanding Dissociation Constants
- The dissociation constant for the weak acid, HA, is given as:
- Ka = 2 × 10^-5
- The dissociation constant for the weak base, BOH, is given as:
- Kb = 5 × 10^-6
Step 2: Writing the Neutralization Reaction
- The neutralization reaction can be represented as:
- HA + BOH ⇌ A- + H2O + B+
Step 3: Equilibrium Constant for Neutralization
- The equilibrium constant for the neutralization reaction (Kneutralization) can be derived from the relationship between the dissociation constants of the acid and base:
Kneutralization = Kw / (Ka * Kb)
- Where Kw is the ion product of water, approximately 1 × 10^-14 at room temperature.
Step 4: Calculating Kneutralization
- First, calculate the product of Ka and Kb:
- Ka * Kb = (2 × 10^-5) * (5 × 10^-6) = 1 × 10^-10
- Now, substitute into the equilibrium constant equation:
- Kneutralization = (1 × 10^-14) / (1 × 10^-10) = 10^4
Final Result
- Thus, the equilibrium constant for the neutralization reaction of the weak acid HA and the weak base BOH is:
- Kneutralization = 10^4
This indicates a favorable reaction towards the formation of water and the conjugate base.
Step 1: Understanding Dissociation Constants
- The dissociation constant for the weak acid, HA, is given as:
- Ka = 2 × 10^-5
- The dissociation constant for the weak base, BOH, is given as:
- Kb = 5 × 10^-6
Step 2: Writing the Neutralization Reaction
- The neutralization reaction can be represented as:
- HA + BOH ⇌ A- + H2O + B+
Step 3: Equilibrium Constant for Neutralization
- The equilibrium constant for the neutralization reaction (Kneutralization) can be derived from the relationship between the dissociation constants of the acid and base:
Kneutralization = Kw / (Ka * Kb)
- Where Kw is the ion product of water, approximately 1 × 10^-14 at room temperature.
Step 4: Calculating Kneutralization
- First, calculate the product of Ka and Kb:
- Ka * Kb = (2 × 10^-5) * (5 × 10^-6) = 1 × 10^-10
- Now, substitute into the equilibrium constant equation:
- Kneutralization = (1 × 10^-14) / (1 × 10^-10) = 10^4
Final Result
- Thus, the equilibrium constant for the neutralization reaction of the weak acid HA and the weak base BOH is:
- Kneutralization = 10^4
This indicates a favorable reaction towards the formation of water and the conjugate base.
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Plz anyone solve me this question.The dissociation cnstant of a weak acid HA and a weak base BOH are 2×10^-5 and 5×10^-6 respectively.The equilibrium constant for the neutralisation reaction of the two is(ignore hydrolysis of resulting salt)?
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Plz anyone solve me this question.The dissociation cnstant of a weak acid HA and a weak base BOH are 2×10^-5 and 5×10^-6 respectively.The equilibrium constant for the neutralisation reaction of the two is(ignore hydrolysis of resulting salt)? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Plz anyone solve me this question.The dissociation cnstant of a weak acid HA and a weak base BOH are 2×10^-5 and 5×10^-6 respectively.The equilibrium constant for the neutralisation reaction of the two is(ignore hydrolysis of resulting salt)? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Plz anyone solve me this question.The dissociation cnstant of a weak acid HA and a weak base BOH are 2×10^-5 and 5×10^-6 respectively.The equilibrium constant for the neutralisation reaction of the two is(ignore hydrolysis of resulting salt)?.
Plz anyone solve me this question.The dissociation cnstant of a weak acid HA and a weak base BOH are 2×10^-5 and 5×10^-6 respectively.The equilibrium constant for the neutralisation reaction of the two is(ignore hydrolysis of resulting salt)? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Plz anyone solve me this question.The dissociation cnstant of a weak acid HA and a weak base BOH are 2×10^-5 and 5×10^-6 respectively.The equilibrium constant for the neutralisation reaction of the two is(ignore hydrolysis of resulting salt)? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Plz anyone solve me this question.The dissociation cnstant of a weak acid HA and a weak base BOH are 2×10^-5 and 5×10^-6 respectively.The equilibrium constant for the neutralisation reaction of the two is(ignore hydrolysis of resulting salt)?.
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