**Questions from DC Pandey's Book:**

1. **Chapter: Mechanics**
- Q1: A body is thrown upwards with an initial velocity of 20 m/s. Calculate the maximum height reached by the body.
- Q2: A car is moving with a uniform acceleration of 2 m/s². If it covers a distance of 100 m in 10 seconds, calculate its initial velocity.
- Q3: A projectile is launched at an angle of 30° with the horizontal and with an initial speed of 50 m/s. Calculate the maximum height reached by the projectile and the time taken to reach the maximum height.

2. **Chapter: Waves and Thermodynamics**
- Q1: A wave is traveling in a medium with a velocity of 300 m/s. If its frequency is 500 Hz, calculate the wavelength of the wave.
- Q2: An ideal gas undergoes an isothermal process. If the initial pressure is 2 atm and the final pressure is 4 atm, calculate the change in volume of the gas.
- Q3: A metal rod of length 1 m is heated from 20°C to 80°C. If the coefficient of linear expansion of the metal is 1.2 x 10^-5 /°C, calculate the change in length of the rod.

3. **Chapter: Electricity and Magnetism**
- Q1: In a circuit, a resistor of 10 Ω is connected in series with a capacitor of capacitance 2 μF. If the current flowing through the circuit is 2 A, calculate the voltage across the capacitor.
- Q2: A wire of length 1 m is carrying a current of 5 A. If the magnetic field at a distance of 0.5 m from the wire is 2 T, calculate the force experienced by a charge of 1 C placed at that point.
- Q3: Two parallel plate capacitors, each of capacitance 5 μF, are connected in parallel. If a potential difference of 10 V is applied across the combination, calculate the total charge stored in the capacitors.

**Solutions for NEET Physics by DC Pandey:**

- Solution 1: To calculate the maximum height reached by a body thrown upwards, we can use the kinematic equation:
- v² = u² + 2as, where v = 0 (at maximum height), u = 20 m/s (initial velocity), a = -9.8 m/s² (acceleration due to gravity).
- Substituting the values, 0 = (20)² + 2(-9.8)s, solving for s gives us s = 20.4 m.
- Therefore, the maximum height reached by the body is 20.4 m.

- Solution 2: If a car covers a distance of 100 m in 10 seconds with a uniform acceleration of 2 m/s², we can use the equation:
- s = ut + (1/2)at², where s = 100 m (distance), t = 10 s (time), a = 2 m/s² (acceleration).
- Rearranging the equation, we get u = (s - (1/2)at²) / t = (100 - (1/2)(2)(10

People choose simple book in physics but we choose standard book in physics to improve the concept and for compitation like dr pramod agrawal and for iit HC VERMA and dc pandey is only for easy compitation it doesn't give confident in problem solving