The average age of a man and his two twin sons is 30 years. The ratio ...
Let father's age be M and age of twins be 2x
(M + 2x)/3 = 30
M + 2x = 90------------(1)
M/x = 5/2
2M = 5x---------------(2)
Multiply (1) with 2
We get, 2M + 4x = 180--------------(3)
Putting (2) in (3)
5x+4x = 180 => 9x = 180x = 20. [his children are twins so 2x = 40]Since M + 2x = 90M = 90 -40 = 50years
The average age of a man and his two twin sons is 30 years. The ratio ...
Let the father's age be x years.
Then the age of one of his twin sons = (30 - x)/2 years (as the average age of the three is 30)
According to the given ratio, we have:
x/(30 - x)/2 = 5/2
Simplifying this, we get:
x = 50 years
Therefore, the father's age is 50 years.
Hence, option A is the correct answer.