To find the pH of the resulting solution, we need to consider the reaction between the HCl and NaCl.

1. Reaction between HCl and NaCl:
HCl is a strong acid, while NaCl is a neutral salt. When HCl is added to water, it completely dissociates to form H+ ions and Cl- ions. NaCl also dissociates in water to form Na+ ions and Cl- ions. Therefore, in the resulting solution, we will have H+, Na+, and Cl- ions.

2. pH calculation:
pH is a measure of the concentration of H+ ions in a solution. To calculate the pH, we need to find the concentration of H+ ions in the resulting solution.

Given that 1c.c. of 0.1N HCl is added to 99c.c. of the aqueous solution of NaCl, we can assume that the final volume of the solution is 100c.c.

Since the concentration of HCl is 0.1N, it means that in 1 liter of HCl solution, there are 0.1 moles of HCl. Therefore, in 1c.c. of HCl solution, there will be (0.1/1000) moles of HCl.

Since we added 1c.c. of HCl to a final volume of 100c.c., the concentration of HCl in the resulting solution is (0.1/1000) moles/100c.c. = 0.001 moles/liter.

Since HCl is a strong acid, it completely dissociates in water to form H+ ions. Therefore, the concentration of H+ ions in the resulting solution is also 0.001 moles/liter.

3. Calculation of pH:
pH is calculated as the negative logarithm (base 10) of the H+ ion concentration.

pH = -log[H+]

pH = -log(0.001) = -(-3) = 3

Therefore, the pH of the resulting solution will be 3.

The correct answer is option 'B' (4)