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A moving hydrogen atom makes a head on collision with stationary hydrogen atom.befre collision both atoms are in ground state and after collison they move together.what is the minimum value of kinetic energy of moving hydrogen atom,such that one of the atom reaches one of the excitation state?ans:20.4 eV?
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A moving hydrogen atom makes a head on collision with stationary hydro...
Minimum Kinetic Energy for Excitation of Hydrogen Atom
To determine the minimum kinetic energy required for the excitation of a hydrogen atom, let's consider a head-on collision between a moving hydrogen atom and a stationary hydrogen atom. Before the collision, both atoms are in their ground state, and after the collision, they move together.
1. Ground State of a Hydrogen Atom
The ground state of a hydrogen atom refers to the state in which the electron is in its lowest energy level, known as the n=1 state. The energy of the ground state is given by the formula:
E1 = -13.6 eV
2. Excitation State of a Hydrogen Atom
An excitation state of a hydrogen atom occurs when the electron transitions from a lower energy level to a higher energy level. Each energy level is defined by a specific value of n. The energy of an excitation state can be calculated using the formula:
En = -13.6 eV / n^2
Where n is the principal quantum number of the energy level.
3. Conservation of Momentum and Energy
During the head-on collision, the total momentum before and after the collision remains constant. Additionally, the total energy before and after the collision is conserved.
4. Calculation of Minimum Kinetic Energy
To calculate the minimum kinetic energy required for excitation, we need to find the maximum energy that can be transferred to the stationary hydrogen atom. This occurs when the moving hydrogen atom comes to a complete stop after the collision. The maximum energy transfer is given by:
Emax = E1 - En
For the minimum kinetic energy of the moving hydrogen atom, we subtract the maximum energy transfer from the energy of the ground state:
Kmin = Emax + E1
5. Calculation and Result
Substituting the values, we have:
Emax = (-13.6 eV) - (-13.6 eV / n^2)
E1 = -13.6 eV
For the minimum kinetic energy, we sum the two values:
Kmin = Emax + E1
For n=2, the minimum kinetic energy is:
Kmin = (-13.6 eV) - (-13.6 eV / 2^2) + (-13.6 eV) = 20.4 eV
Therefore, the minimum kinetic energy required for the hydrogen atom to reach the first excitation state is 20.4 eV.
To determine the minimum kinetic energy required for the excitation of a hydrogen atom, let's consider a head-on collision between a moving hydrogen atom and a stationary hydrogen atom. Before the collision, both atoms are in their ground state, and after the collision, they move together.
1. Ground State of a Hydrogen Atom
The ground state of a hydrogen atom refers to the state in which the electron is in its lowest energy level, known as the n=1 state. The energy of the ground state is given by the formula:
E1 = -13.6 eV
2. Excitation State of a Hydrogen Atom
An excitation state of a hydrogen atom occurs when the electron transitions from a lower energy level to a higher energy level. Each energy level is defined by a specific value of n. The energy of an excitation state can be calculated using the formula:
En = -13.6 eV / n^2
Where n is the principal quantum number of the energy level.
3. Conservation of Momentum and Energy
During the head-on collision, the total momentum before and after the collision remains constant. Additionally, the total energy before and after the collision is conserved.
4. Calculation of Minimum Kinetic Energy
To calculate the minimum kinetic energy required for excitation, we need to find the maximum energy that can be transferred to the stationary hydrogen atom. This occurs when the moving hydrogen atom comes to a complete stop after the collision. The maximum energy transfer is given by:
Emax = E1 - En
For the minimum kinetic energy of the moving hydrogen atom, we subtract the maximum energy transfer from the energy of the ground state:
Kmin = Emax + E1
5. Calculation and Result
Substituting the values, we have:
Emax = (-13.6 eV) - (-13.6 eV / n^2)
E1 = -13.6 eV
For the minimum kinetic energy, we sum the two values:
Kmin = Emax + E1
For n=2, the minimum kinetic energy is:
Kmin = (-13.6 eV) - (-13.6 eV / 2^2) + (-13.6 eV) = 20.4 eV
Therefore, the minimum kinetic energy required for the hydrogen atom to reach the first excitation state is 20.4 eV.
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A moving hydrogen atom makes a head on collision with stationary hydrogen atom.befre collision both atoms are in ground state and after collison they move together.what is the minimum value of kinetic energy of moving hydrogen atom,such that one of the atom reaches one of the excitation state?ans:20.4 eV?
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A moving hydrogen atom makes a head on collision with stationary hydrogen atom.befre collision both atoms are in ground state and after collison they move together.what is the minimum value of kinetic energy of moving hydrogen atom,such that one of the atom reaches one of the excitation state?ans:20.4 eV? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A moving hydrogen atom makes a head on collision with stationary hydrogen atom.befre collision both atoms are in ground state and after collison they move together.what is the minimum value of kinetic energy of moving hydrogen atom,such that one of the atom reaches one of the excitation state?ans:20.4 eV? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A moving hydrogen atom makes a head on collision with stationary hydrogen atom.befre collision both atoms are in ground state and after collison they move together.what is the minimum value of kinetic energy of moving hydrogen atom,such that one of the atom reaches one of the excitation state?ans:20.4 eV?.
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