Calculation of Meiotic Divisions Required

To form 500 zygotes, we need a total of 1000 gametes (500 from male and 500 from female).

In males, one meiotic division forms 4 male gametes, so the number of meiotic divisions required in males is:

1000/4 = 250 meiotic divisions

In females, one meiotic division forms 1 female gamete, so the number of meiotic divisions required in females is:

1000/1 = 1000 meiotic divisions

Therefore, a total of 1250 meiotic divisions are required to form 500 zygotes.

Explanation

Meiosis is the process of cell division that produces gametes in sexually reproducing organisms. During meiosis, a diploid cell undergoes two rounds of cell division, resulting in the formation of four haploid cells (gametes). Each of these gametes contains half the number of chromosomes as the parent cell.

In males, meiosis results in the formation of four haploid cells, each of which develops into a sperm cell. These sperm cells can then fuse with the female gamete (egg cell) during fertilization, resulting in the formation of a zygote.

In females, meiosis results in the formation of one haploid cell (the egg cell), which can also fuse with a sperm cell during fertilization to form a zygote.

In order to form 500 zygotes, we need a total of 1000 gametes (500 from each parent). This means that a total of 1250 meiotic divisions are required (250 in males and 1000 in females) to produce the necessary number of gametes.

Conclusion

Meiosis is a crucial process in sexual reproduction, as it ensures that the resulting offspring have the correct number of chromosomes and genetic variation. The number of meiotic divisions required to produce a given number of gametes depends on the sex of the organism and the number of gametes required.

In male4 male gamete=1meiosis500 male gamete= 1/4 × 500 =125 meiosisIn female1 egg=1 meiosis500 eggs=500 meiosisTotal=500+125 =625 meiotic divisions