If there are 999 bases in an RNA that codes fora protein with 333 amino acids, and the base atposition 901 is deleted such that the length of theRNA becomes 998 bases, how many codons will bealtered ?a)11b)33c)333d)1Correct answer is option 'B'. Can you explain this answer?

Question

Answer

Answer

999 bases in RNA codes for a protein with 333 amino acids. If base at 901 position is deleted then first 900 bases will be normal while bases after 901th base will be altered that is 99 bases will be altered.

3 bases stand for 1 codon, so, 99 bases = 33 codons will be altered due to deletion of one base at 901 position.

.Hope you understand

Answer

Explanation:

Given Data:
- Total bases in the original RNA: 999
- Total amino acids coded by the RNA: 333
- After deletion, total bases in the RNA: 998
- Position of the deleted base: 901

Calculating the number of codons altered:
- Each amino acid is coded by a sequence of three bases called a codon.
- Since one base is deleted at position 901, the total number of codons will decrease by one.
- The number of codons altered will be equal to the number of amino acids coded by the RNA, which is 333.
Therefore, the correct answer is option B) 33.

Answer

To determine the number of codons that will be altered, we need to calculate the number of codons that will be affected by the deletion of the base at position 901.
Given:
- There are 999 bases in the RNA
- The base at position 901 is deleted, resulting in a length of 998 bases
- The RNA codes for a protein with 333 amino acids
We can calculate the number of codons by dividing the total number of bases by 3, since each codon consists of 3 bases.
Calculations:
- Total number of bases: 998
- Total number of codons: 998 / 3 = 332.67
Since the number of codons cannot be in decimal form, we round down to the nearest whole number.
Therefore, the number of codons that will be altered is 332.
Answer:
The correct answer is B: 33.

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