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Uniform magnetic field B is directed vertically upward and 3wires of equal length L, carrying equal current I are lying in a horizontal plane such that the first one is along north , second one along north east and the third one at 60degree north of east . Force exerted by magnetic field B on them is (1)zero on the first (2)BIL/√2 on the second (3)√3BIL on the third (4) BIL on all of them ? Correct option (4) explain it please?
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Explanation:
Force on a Current-Carrying Wire:
When a wire carrying current I is placed in a magnetic field B, a force is exerted on the wire. This force is given by the formula:
F = BIL sinθ
where F is the force, B is the magnetic field, I is the current, L is the length of the wire, and θ is the angle between the direction of the current and the magnetic field.
Force on the First Wire:
The first wire is aligned along the north direction, which is perpendicular to the magnetic field B. Therefore, the angle θ between the current and the magnetic field is 90 degrees. In this case, sinθ = sin(90°) = 1. Plugging this into the formula, we get:
F = BIL sinθ = BIL (1) = BIL
So the force exerted on the first wire is BIL.
Force on the Second Wire:
The second wire is aligned along the northeast direction. To find the force on this wire, we need to find the angle θ between the current and the magnetic field. The angle between the north direction and the northeast direction is 45 degrees. Since the magnetic field is directed vertically upward, it is perpendicular to the northeast direction. Therefore, the angle between the current and the magnetic field is 45 degrees. Plugging this into the formula, we get:
F = BIL sinθ = BIL sin(45°) = BIL/√2
So the force exerted on the second wire is BIL/√2.
Force on the Third Wire:
The third wire is at an angle of 60 degrees north of east. To find the force on this wire, we need to find the angle θ between the current and the magnetic field. The angle between the east direction and the direction 60 degrees north of east is 30 degrees. Since the magnetic field is directed vertically upward, it is perpendicular to the direction 60 degrees north of east. Therefore, the angle between the current and the magnetic field is 30 degrees. Plugging this into the formula, we get:
F = BIL sinθ = BIL sin(30°) = BIL/2
So the force exerted on the third wire is BIL/2.
Conclusion:
The force exerted by the magnetic field B on the three wires is different. The first wire experiences a force of BIL, the second wire experiences a force of BIL/√2, and the third wire experiences a force of BIL/2. Therefore, the correct option is (4) BIL on all of them.
Force on a Current-Carrying Wire:
When a wire carrying current I is placed in a magnetic field B, a force is exerted on the wire. This force is given by the formula:
F = BIL sinθ
where F is the force, B is the magnetic field, I is the current, L is the length of the wire, and θ is the angle between the direction of the current and the magnetic field.
Force on the First Wire:
The first wire is aligned along the north direction, which is perpendicular to the magnetic field B. Therefore, the angle θ between the current and the magnetic field is 90 degrees. In this case, sinθ = sin(90°) = 1. Plugging this into the formula, we get:
F = BIL sinθ = BIL (1) = BIL
So the force exerted on the first wire is BIL.
Force on the Second Wire:
The second wire is aligned along the northeast direction. To find the force on this wire, we need to find the angle θ between the current and the magnetic field. The angle between the north direction and the northeast direction is 45 degrees. Since the magnetic field is directed vertically upward, it is perpendicular to the northeast direction. Therefore, the angle between the current and the magnetic field is 45 degrees. Plugging this into the formula, we get:
F = BIL sinθ = BIL sin(45°) = BIL/√2
So the force exerted on the second wire is BIL/√2.
Force on the Third Wire:
The third wire is at an angle of 60 degrees north of east. To find the force on this wire, we need to find the angle θ between the current and the magnetic field. The angle between the east direction and the direction 60 degrees north of east is 30 degrees. Since the magnetic field is directed vertically upward, it is perpendicular to the direction 60 degrees north of east. Therefore, the angle between the current and the magnetic field is 30 degrees. Plugging this into the formula, we get:
F = BIL sinθ = BIL sin(30°) = BIL/2
So the force exerted on the third wire is BIL/2.
Conclusion:
The force exerted by the magnetic field B on the three wires is different. The first wire experiences a force of BIL, the second wire experiences a force of BIL/√2, and the third wire experiences a force of BIL/2. Therefore, the correct option is (4) BIL on all of them.
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Uniform magnetic field B is directed vertically upward and 3wires of equal length L, carrying equal current I are lying in a horizontal plane such that the first one is along north , second one along north east and the third one at 60degree north of east . Force exerted by magnetic field B on them is (1)zero on the first (2)BIL/√2 on the second (3)√3BIL on the third (4) BIL on all of them ? Correct option (4) explain it please?
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Uniform magnetic field B is directed vertically upward and 3wires of equal length L, carrying equal current I are lying in a horizontal plane such that the first one is along north , second one along north east and the third one at 60degree north of east . Force exerted by magnetic field B on them is (1)zero on the first (2)BIL/√2 on the second (3)√3BIL on the third (4) BIL on all of them ? Correct option (4) explain it please? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Uniform magnetic field B is directed vertically upward and 3wires of equal length L, carrying equal current I are lying in a horizontal plane such that the first one is along north , second one along north east and the third one at 60degree north of east . Force exerted by magnetic field B on them is (1)zero on the first (2)BIL/√2 on the second (3)√3BIL on the third (4) BIL on all of them ? Correct option (4) explain it please? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Uniform magnetic field B is directed vertically upward and 3wires of equal length L, carrying equal current I are lying in a horizontal plane such that the first one is along north , second one along north east and the third one at 60degree north of east . Force exerted by magnetic field B on them is (1)zero on the first (2)BIL/√2 on the second (3)√3BIL on the third (4) BIL on all of them ? Correct option (4) explain it please?.
Uniform magnetic field B is directed vertically upward and 3wires of equal length L, carrying equal current I are lying in a horizontal plane such that the first one is along north , second one along north east and the third one at 60degree north of east . Force exerted by magnetic field B on them is (1)zero on the first (2)BIL/√2 on the second (3)√3BIL on the third (4) BIL on all of them ? Correct option (4) explain it please? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Uniform magnetic field B is directed vertically upward and 3wires of equal length L, carrying equal current I are lying in a horizontal plane such that the first one is along north , second one along north east and the third one at 60degree north of east . Force exerted by magnetic field B on them is (1)zero on the first (2)BIL/√2 on the second (3)√3BIL on the third (4) BIL on all of them ? Correct option (4) explain it please? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Uniform magnetic field B is directed vertically upward and 3wires of equal length L, carrying equal current I are lying in a horizontal plane such that the first one is along north , second one along north east and the third one at 60degree north of east . Force exerted by magnetic field B on them is (1)zero on the first (2)BIL/√2 on the second (3)√3BIL on the third (4) BIL on all of them ? Correct option (4) explain it please?.
Solutions for Uniform magnetic field B is directed vertically upward and 3wires of equal length L, carrying equal current I are lying in a horizontal plane such that the first one is along north , second one along north east and the third one at 60degree north of east . Force exerted by magnetic field B on them is (1)zero on the first (2)BIL/√2 on the second (3)√3BIL on the third (4) BIL on all of them ? Correct option (4) explain it please? in English & in Hindi are available as part of our courses for NEET.
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