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An isolated particle of mass m is moving in a horizontal plane along the x-axis at a certain height above the ground. It suddenly explodes into two fragments of masses m/4 and 3m/4. An instant later, the smaller fragment is at y = 15 cm. The larger fragment at this instant is at
- a)y = - 5 cm
- b)y = + 20 cm
- c)y = + 5 cm
- d)y = - 20 cm
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
An isolated particle of mass m is moving in a horizontal plane along t...
Before explosion particle was moving along x-axis i.e. it has no y-component of velocity. Therefore the centre of
mass will not move in y-direction or we can say ycm = 0.
mass will not move in y-direction or we can say ycm = 0.
Now, ycm = 
Most Upvoted Answer
An isolated particle of mass m is moving in a horizontal plane along t...
Solve this on
m1y1 = - m2y2
m/4 x 15 = - 3m/4 x Y2
Y2 = - 5cm
m1y1 = - m2y2
m/4 x 15 = - 3m/4 x Y2
Y2 = - 5cm
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An isolated particle of mass m is moving in a horizontal plane along t...
Given:
- Particle of mass m is moving in a horizontal plane along the x-axis.
- It suddenly explodes into two fragments of masses m/4 and 3m/4.
- Smaller fragment is at y = 15 cm.
To find:
The position of the larger fragment at this instant.
Solution:
1. Since the explosion is in a horizontal plane, the x-component of the total momentum before the explosion is equal to the x-component of the total momentum after the explosion.
2. Before the explosion, the particle has momentum m * v (where v is the initial velocity of the particle).
3. After the explosion, the smaller fragment of mass m/4 moves with a velocity v1, and the larger fragment of mass 3m/4 moves with a velocity v2.
4. Using the principle of conservation of momentum in the x-direction, we can write:
m * v = (m/4) * v1 + (3m/4) * v2
Step 1: Find the velocities of the fragments
5. Since the masses are given in terms of m, we can simplify the equation as:
v = (1/4) * v1 + (3/4) * v2
Step 2: Find the position of the larger fragment
6. Let's assume that the initial position of the particle is x = 0.
7. Since the smaller fragment is at y = 15 cm, we can assume that the smaller fragment moves in the positive y-direction.
8. Considering the time interval after the explosion, the smaller fragment moves a certain distance in the y-direction.
9. In the given options, option 'A' corresponds to y = -5 cm, which means the larger fragment moves in the negative y-direction.
10. Therefore, the correct answer is option 'A' - y = -5 cm.
- Particle of mass m is moving in a horizontal plane along the x-axis.
- It suddenly explodes into two fragments of masses m/4 and 3m/4.
- Smaller fragment is at y = 15 cm.
To find:
The position of the larger fragment at this instant.
Solution:
1. Since the explosion is in a horizontal plane, the x-component of the total momentum before the explosion is equal to the x-component of the total momentum after the explosion.
2. Before the explosion, the particle has momentum m * v (where v is the initial velocity of the particle).
3. After the explosion, the smaller fragment of mass m/4 moves with a velocity v1, and the larger fragment of mass 3m/4 moves with a velocity v2.
4. Using the principle of conservation of momentum in the x-direction, we can write:
m * v = (m/4) * v1 + (3m/4) * v2
Step 1: Find the velocities of the fragments
5. Since the masses are given in terms of m, we can simplify the equation as:
v = (1/4) * v1 + (3/4) * v2
Step 2: Find the position of the larger fragment
6. Let's assume that the initial position of the particle is x = 0.
7. Since the smaller fragment is at y = 15 cm, we can assume that the smaller fragment moves in the positive y-direction.
8. Considering the time interval after the explosion, the smaller fragment moves a certain distance in the y-direction.
9. In the given options, option 'A' corresponds to y = -5 cm, which means the larger fragment moves in the negative y-direction.
10. Therefore, the correct answer is option 'A' - y = -5 cm.
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An isolated particle of mass m is moving in a horizontal plane along the x-axis at a certain height above the ground. It suddenly explodes into two fragments of masses m/4 and 3m/4. An instant later, the smaller fragment is at y = 15 cm. The larger fragment at this instant is ata)y = - 5 cmb)y = + 20 cmc)y = + 5 cmd)y = - 20 cmCorrect answer is option 'A'. Can you explain this answer?
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An isolated particle of mass m is moving in a horizontal plane along the x-axis at a certain height above the ground. It suddenly explodes into two fragments of masses m/4 and 3m/4. An instant later, the smaller fragment is at y = 15 cm. The larger fragment at this instant is ata)y = - 5 cmb)y = + 20 cmc)y = + 5 cmd)y = - 20 cmCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An isolated particle of mass m is moving in a horizontal plane along the x-axis at a certain height above the ground. It suddenly explodes into two fragments of masses m/4 and 3m/4. An instant later, the smaller fragment is at y = 15 cm. The larger fragment at this instant is ata)y = - 5 cmb)y = + 20 cmc)y = + 5 cmd)y = - 20 cmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An isolated particle of mass m is moving in a horizontal plane along the x-axis at a certain height above the ground. It suddenly explodes into two fragments of masses m/4 and 3m/4. An instant later, the smaller fragment is at y = 15 cm. The larger fragment at this instant is ata)y = - 5 cmb)y = + 20 cmc)y = + 5 cmd)y = - 20 cmCorrect answer is option 'A'. Can you explain this answer?.
An isolated particle of mass m is moving in a horizontal plane along the x-axis at a certain height above the ground. It suddenly explodes into two fragments of masses m/4 and 3m/4. An instant later, the smaller fragment is at y = 15 cm. The larger fragment at this instant is ata)y = - 5 cmb)y = + 20 cmc)y = + 5 cmd)y = - 20 cmCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An isolated particle of mass m is moving in a horizontal plane along the x-axis at a certain height above the ground. It suddenly explodes into two fragments of masses m/4 and 3m/4. An instant later, the smaller fragment is at y = 15 cm. The larger fragment at this instant is ata)y = - 5 cmb)y = + 20 cmc)y = + 5 cmd)y = - 20 cmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An isolated particle of mass m is moving in a horizontal plane along the x-axis at a certain height above the ground. It suddenly explodes into two fragments of masses m/4 and 3m/4. An instant later, the smaller fragment is at y = 15 cm. The larger fragment at this instant is ata)y = - 5 cmb)y = + 20 cmc)y = + 5 cmd)y = - 20 cmCorrect answer is option 'A'. Can you explain this answer?.
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