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A ray of light enters into benzene from air.If the refractive index of benzene is 1.50,by what percent does the speed of light reduce on entering the benzene?
Most Upvoted Answer
A ray of light enters into benzene from air.If the refractive index of...
Let c be speed of light in vaccum and v be speed of light in benzene.

Refractive index of benzene=1.5=speed of light in vaccum/speed of light in benzene.

c/v=1.5
v=2/3c

Percentage reduce in speed of light

=(c-v/c)*100

=(1/3)*100=33.33%

That's all🙂
Community Answer
A ray of light enters into benzene from air.If the refractive index of...
Explanation:

When a ray of light enters a medium, it slows down due to the properties of the medium. The amount of slowing down depends on the refractive index of the medium. Refractive index is defined as the ratio of speed of light in vacuum to the speed of light in the medium.


Formula:

Refraction index = Speed of light in vacuum / Speed of light in medium


Calculation:

Given, refractive index of benzene = 1.50

Speed of light in vacuum = 3 x 10^8 m/s (constant)

Speed of light in benzene = Speed of light in vacuum / Refractive index of benzene = 2 x 10^8 m/s


Percentage reduction in speed:

Reduction in speed of light = Speed of light in vacuum - Speed of light in benzene = 1 x 10^8 m/s

Percentage reduction in speed of light = (Reduction in speed / Speed of light in vacuum) x 100%

Percentage reduction in speed of light = (1 x 10^8 / 3 x 10^8) x 100% = 33.33%


Conclusion:

The speed of light reduces by 33.33% on entering benzene from air. This reduction in speed is due to the higher refractive index of benzene compared to air.
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A ray of light enters into benzene from air.If the refractive index of benzene is 1.50,by what percent does the speed of light reduce on entering the benzene?
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