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The deceleration of a car travelling on a straight highway is a function of its instantaneous velocity v given by w=a sqrt v ,where a is a constant.if the initial velocity of the car is 60km/hr the distance the car will travel and the time it takes to stop are?? 1)3/2a m,1/2a s 2)2/3a m,2/a s. (s stands for seconds)
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The deceleration of a car travelling on a straight highway is a functi...
Solution:

Given, w = a sqrt v, where a is a constant.

Initial velocity, u = 60 km/hr = 16.67 m/s (1 km/hr = 5/18 m/s)

Let the final velocity be 0 m/s.

We know that, v^2 = u^2 - 2as

At the point of stopping, v = 0, a = w = a sqrt v

∴ v = a sqrt v

Squaring both sides, we get

v^2 = a^2 v

∴ v = a^2 v / v

a^2 = 1

a = ± 1 (since a is a positive constant, we take a = 1)

Now, w = a sqrt v = sqrt v

Given, w = dw/dt = a sqrt v

∴ dw/dt = sqrt v

Integrating both sides, we get

∫dw = ∫sqrt v dt

w = (2/3)v^(3/2) + C1

At t = 0, w = a sqrt v

∴ C1 = -2/3

Therefore, w = (2/3)(v^(3/2) - sqrt v)

At the point of stopping, v = 0, w = a sqrt v = 0

∴ (2/3)(0 - 0) = (2/3)(u^(3/2))

∴ u^(3/2) = 0

∴ u = 0

The car will not stop at all as the initial velocity is 16.67 m/s and the final velocity should be 0 m/s.

Hence, the given options are incorrect.

Note: The problem statement may have some errors, as the car cannot stop with the given initial velocity and the given function for deceleration.
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The deceleration of a car travelling on a straight highway is a functi...
Bro do u have solution for this
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The deceleration of a car travelling on a straight highway is a function of its instantaneous velocity v given by w=a sqrt v ,where a is a constant.if the initial velocity of the car is 60km/hr the distance the car will travel and the time it takes to stop are?? 1)3/2a m,1/2a s 2)2/3a m,2/a s. (s stands for seconds)
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