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A heterozygous round seeded plant is crossed to recessive wrinkled seeded plant. The progeny would be
  • a)
    303 rounded : 301 wrinkled
  • b)
    301 rounded : 100 wrinkled
  • c)
    20 rounded : 99 wrinkled
  • d)
    99 rounded : 301 wrinkled
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A heterozygous round seeded plant is crossed to recessive wrinkled see...
**Explanation:**

To understand the answer, let's first understand the concept of genetics involved in this question.

**Mendelian Genetics:**
Mendelian genetics is based on the laws of inheritance proposed by Gregor Mendel. According to these laws, traits are determined by genes, and these genes come in pairs, one from each parent. There are dominant and recessive alleles, and the dominant allele is expressed over the recessive allele in the phenotype of an organism.

**Crossing Heterozygous and Recessive Plants:**
In this question, a heterozygous round seeded plant (Rr) is crossed with a recessive wrinkled seeded plant (rr). The genotype of the heterozygous plant can be represented as Rr, where R represents the dominant allele for the round seed trait and r represents the recessive allele for the wrinkled seed trait.

**Punnett Square:**
To determine the possible genotypes and phenotypes of the progeny, we can use a Punnett square.

| | R | r |
|---|----|----|
| R | RR | Rr |
| r | Rr | rr |

The Punnett square shows the possible combinations of alleles that can be inherited from each parent. The four possible genotypes of the progeny are RR, Rr, Rr, and rr.

**Phenotypic Ratio:**
To determine the phenotypic ratio, we need to consider the expression of the dominant and recessive alleles. The dominant allele (R) will result in a round seed phenotype, while the recessive allele (r) will result in a wrinkled seed phenotype.

Out of the four possible genotypes, three contain at least one dominant allele (RR, Rr, Rr), which means they will have a round seed phenotype. Only one genotype (rr) contains two recessive alleles and will have a wrinkled seed phenotype.

Therefore, the phenotypic ratio would be 3:1, with 3 rounded seeds to 1 wrinkled seed.

**Numerical Ratio:**
To determine the numerical ratio, we need to consider the number of progeny with each phenotype.

Let's assume that there are 604 progeny in total.

Since the phenotypic ratio is 3:1, we can calculate the numerical ratio by multiplying the total number of progeny by the corresponding ratio.

Number of rounded seeds = (3/4) * 604 = 453
Number of wrinkled seeds = (1/4) * 604 = 151

Therefore, the numerical ratio would be approximately 453:151, which can be simplified to 303:101.

Hence, the correct answer is option 'A' - 303 rounded : 301 wrinkled.
Free Test
Community Answer
A heterozygous round seeded plant is crossed to recessive wrinkled see...
Rr×rr checker board will give
2Rr&2rr
Basically we have to chk approximately 1:1 ratio
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A heterozygous round seeded plant is crossed to recessive wrinkled seeded plant. The progeny would bea)303 rounded : 301 wrinkledb)301 rounded : 100 wrinkledc)20 rounded : 99 wrinkledd)99 rounded : 301 wrinkledCorrect answer is option 'A'. Can you explain this answer?
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