A pea plant with yellow and round seeds is crossed with another pea pl...
Possible answer:
Genotype of pea plant with yellow round seeds
Based on the given information, we can use a Punnett square to analyze the possible genetic outcomes of the cross between the two pea plants:
Parent 1: YYRR (yellow round)
Parent 2: yyrr (green wrinkled)
The capital letters represent dominant alleles for yellow color and round shape, while the lowercase letters represent recessive alleles for green color and wrinkled shape. The gametes of each parent can be shown as follows:
Parent 1: YR
Parent 2: yr
The possible combinations of these gametes in the offspring can be shown in a 4x4 Punnett square:
YR Yr yR yr
YR YYRR YYRr YyRR YyRr
Yr YYRr YYrr YyRr Yyrr
yR YyRR YyRr yyRR yyRr
yr YyRr Yyrr yyRr yyrr
The phenotypic ratio of the offspring is 1:1:1:1 for yellow round, yellow wrinkled, green round, and green wrinkled, as expected from a dihybrid cross. However, the given data specify that out of 100 seeds, 51 are yellow round and 49 are yellow wrinkled. This means that the other two phenotypes are absent or too few to be detected, most likely due to a lack of genetic diversity or random chance.
To determine the genotype of the pea plant with yellow round seeds, we can use the principle of segregation and assume that it is heterozygous for both traits. This means that it carries one dominant allele and one recessive allele for yellow color and round shape, and can produce two types of gametes: YR and yR. The other parent must have been homozygous recessive for both traits, since it only contributed the recessive alleles to all the wrinkled seeds.
Therefore, the genotype of the pea plant with yellow round seeds must be YyRr, which can produce four types of gametes in equal proportions: YR, yR, Yr, and yr. When crossed with another YyRr plant or a YYRR or YYRr plant, it can produce a variety of offspring with different phenotypic and genotypic ratios.
A pea plant with yellow and round seeds is crossed with another pea pl...
YYRr
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