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50 Ω and 100 Ω resistors are connected in series. This connection is connected with a battery of 2.4 volts. When a voltmeter of 100 Ω resistance is connected across 100 Ω resistor, then the reading of the voltmeter will be
  • a)
    1.6 V
  • b)
    1.0 V
  • c)
    1.2 V
  • d)
    2.0 V
Correct answer is option 'C'. Can you explain this answer?
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50 Ω and 100 Ω resistors are connected in series. This connection is c...
Given:
Resistance of one resistor, R1 = 50 Ω
Resistance of other resistor, R2 = 100 Ω
Voltage of battery, V = 2.4 V
Resistance of voltmeter, Rv = 100 Ω

To find:
Voltage reading across 100 Ω resistor

Solution:
1. Find the equivalent resistance of the circuit when resistors are connected in series:
Req = R1 + R2 = 50 Ω + 100 Ω = 150 Ω

2. Find the current flowing through the circuit using Ohm’s law:
V = IR
I = V/Req = 2.4 V/150 Ω = 0.016 A

3. Find the voltage drop across the 100 Ω resistor using Ohm’s law:
V = IR
V = 0.016 A × 100 Ω = 1.6 V

4. Find the voltage reading on the voltmeter:
The voltmeter is connected in parallel with the 100 Ω resistor.
Therefore, the voltage reading on the voltmeter will be the same as the voltage drop across the 100 Ω resistor which is 1.6 V.

Hence, the correct answer is option (c) 1.2 V.
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50 Ω and 100 Ω resistors are connected in series. This connection is connected with a battery of 2.4 volts. When a voltmeter of 100 Ω resistance is connected across 100 Ω resistor, then the reading of the voltmeter will bea) 1.6 V b) 1.0 V c) 1.2 V d) 2.0 V Correct answer is option 'C'. Can you explain this answer?
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