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NH2OH can be prepared by electrolysis of aqueous solution of N2H4. The charge required to produce 0.2 mole of NH2OH with 100 % efficiency
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Electrolysis of Aqueous N2H4 Solution to Produce NH2OH
To prepare NH2OH by the electrolysis of an aqueous solution of N2H4, the following steps need to be followed:
- Set up the electrolytic cell: The electrolytic cell consists of two electrodes (anode and cathode) immersed in an aqueous solution of N2H4.
- Pass electric current: When an electric current is passed through the solution, N2H4 undergoes electrolysis at the cathode to form NH2OH and H2 gas.
- Calculate the charge required: The balanced chemical equation for the electrolysis of N2H4 to produce NH2OH is:
N2H4 + 2H2O → NH2OH + 2H2 + 2OH-
From the equation, we can see that 1 mole of N2H4 produces 1 mole of NH2OH. Therefore, to produce 0.2 moles of NH2OH, 0.2 moles of N2H4 are needed.
- Calculate the charge: The Faraday's constant is 96485 C/mol. Since 1 mole of electrons is equivalent to 1 Faraday, the charge required to produce 0.2 moles of NH2OH can be calculated as:
Charge (C) = 0.2 mol * 96485 C/mol = 19297 C
Therefore, a charge of 19297 Coulombs is required to produce 0.2 moles of NH2OH with 100% efficiency. This charge will result in the electrolysis of the N2H4 solution to produce the desired NH2OH.
To prepare NH2OH by the electrolysis of an aqueous solution of N2H4, the following steps need to be followed:
- Set up the electrolytic cell: The electrolytic cell consists of two electrodes (anode and cathode) immersed in an aqueous solution of N2H4.
- Pass electric current: When an electric current is passed through the solution, N2H4 undergoes electrolysis at the cathode to form NH2OH and H2 gas.
- Calculate the charge required: The balanced chemical equation for the electrolysis of N2H4 to produce NH2OH is:
N2H4 + 2H2O → NH2OH + 2H2 + 2OH-
From the equation, we can see that 1 mole of N2H4 produces 1 mole of NH2OH. Therefore, to produce 0.2 moles of NH2OH, 0.2 moles of N2H4 are needed.
- Calculate the charge: The Faraday's constant is 96485 C/mol. Since 1 mole of electrons is equivalent to 1 Faraday, the charge required to produce 0.2 moles of NH2OH can be calculated as:
Charge (C) = 0.2 mol * 96485 C/mol = 19297 C
Therefore, a charge of 19297 Coulombs is required to produce 0.2 moles of NH2OH with 100% efficiency. This charge will result in the electrolysis of the N2H4 solution to produce the desired NH2OH.
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NH2OH can be prepared by electrolysis of aqueous solution of N2H4. The charge required to produce 0.2 mole of NH2OH with 100 % efficiency
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NH2OH can be prepared by electrolysis of aqueous solution of N2H4. The charge required to produce 0.2 mole of NH2OH with 100 % efficiency for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about NH2OH can be prepared by electrolysis of aqueous solution of N2H4. The charge required to produce 0.2 mole of NH2OH with 100 % efficiency covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for NH2OH can be prepared by electrolysis of aqueous solution of N2H4. The charge required to produce 0.2 mole of NH2OH with 100 % efficiency .
NH2OH can be prepared by electrolysis of aqueous solution of N2H4. The charge required to produce 0.2 mole of NH2OH with 100 % efficiency for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about NH2OH can be prepared by electrolysis of aqueous solution of N2H4. The charge required to produce 0.2 mole of NH2OH with 100 % efficiency covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for NH2OH can be prepared by electrolysis of aqueous solution of N2H4. The charge required to produce 0.2 mole of NH2OH with 100 % efficiency .
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