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Order of dissociation of 0.1N CH3COOH is ( dissociation constant = 10^-5) a) 10^-5 b) 10^-4 c) 10^-3 d) 10^-2?
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Order of dissociation of 0.1N CH3COOH is ( dissociation constant = 10^...
Order of dissociation of 0.1N CH3COOH
Dissociation constant (Ka) is a measure of the extent to which a weak acid or base dissociates in a solution. It is given by the ratio of the concentration of the dissociated species to the concentration of the undissociated species.
The dissociation constant of CH3COOH is given as 10^-5. This means that only a small fraction of CH3COOH molecules dissociate into CH3COO- ions and H+ ions in the solution.
To determine the order of dissociation of 0.1N CH3COOH, we need to consider the concentration of the dissociated species and the undissociated species.
1. Concentration of the undissociated species:
In a 0.1N solution, the initial concentration of CH3COOH is 0.1N. Since the dissociation constant is very small (10^-5), we can assume that the concentration of CH3COOH remains almost unchanged. Therefore, the concentration of the undissociated species is approximately 0.1N.
2. Concentration of the dissociated species:
Let's assume x is the concentration (in moles per liter) of the CH3COO- ions and the H+ ions formed due to dissociation of CH3COOH. Since CH3COOH dissociates in a 1:1 ratio, the concentration of both CH3COO- ions and H+ ions will be x.
Using the dissociation constant expression for CH3COOH, we have:
Ka = [CH3COO-][H+]/[CH3COOH]
10^-5 = x * x / 0.1
Simplifying the equation, we have:
10^-5 = x^2 / 0.1
Multiplying both sides by 0.1, we get:
10^-6 = x^2
Taking the square root of both sides, we find:
x = 10^-3
Therefore, the concentration of the dissociated species (CH3COO- ions and H+ ions) is approximately 10^-3 N.
Order of dissociation:
The order of dissociation refers to the power to which the concentration of the dissociated species is raised. In this case, since the concentration of the dissociated species is 10^-3 N, the order of dissociation is 10^-3.
Therefore, the correct answer is c) 10^-3.
Dissociation constant (Ka) is a measure of the extent to which a weak acid or base dissociates in a solution. It is given by the ratio of the concentration of the dissociated species to the concentration of the undissociated species.
The dissociation constant of CH3COOH is given as 10^-5. This means that only a small fraction of CH3COOH molecules dissociate into CH3COO- ions and H+ ions in the solution.
To determine the order of dissociation of 0.1N CH3COOH, we need to consider the concentration of the dissociated species and the undissociated species.
1. Concentration of the undissociated species:
In a 0.1N solution, the initial concentration of CH3COOH is 0.1N. Since the dissociation constant is very small (10^-5), we can assume that the concentration of CH3COOH remains almost unchanged. Therefore, the concentration of the undissociated species is approximately 0.1N.
2. Concentration of the dissociated species:
Let's assume x is the concentration (in moles per liter) of the CH3COO- ions and the H+ ions formed due to dissociation of CH3COOH. Since CH3COOH dissociates in a 1:1 ratio, the concentration of both CH3COO- ions and H+ ions will be x.
Using the dissociation constant expression for CH3COOH, we have:
Ka = [CH3COO-][H+]/[CH3COOH]
10^-5 = x * x / 0.1
Simplifying the equation, we have:
10^-5 = x^2 / 0.1
Multiplying both sides by 0.1, we get:
10^-6 = x^2
Taking the square root of both sides, we find:
x = 10^-3
Therefore, the concentration of the dissociated species (CH3COO- ions and H+ ions) is approximately 10^-3 N.
Order of dissociation:
The order of dissociation refers to the power to which the concentration of the dissociated species is raised. In this case, since the concentration of the dissociated species is 10^-3 N, the order of dissociation is 10^-3.
Therefore, the correct answer is c) 10^-3.
Community Answer
Order of dissociation of 0.1N CH3COOH is ( dissociation constant = 10^...
Option d
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Order of dissociation of 0.1N CH3COOH is ( dissociation constant = 10^-5) a) 10^-5 b) 10^-4 c) 10^-3 d) 10^-2?
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Order of dissociation of 0.1N CH3COOH is ( dissociation constant = 10^-5) a) 10^-5 b) 10^-4 c) 10^-3 d) 10^-2? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Order of dissociation of 0.1N CH3COOH is ( dissociation constant = 10^-5) a) 10^-5 b) 10^-4 c) 10^-3 d) 10^-2? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Order of dissociation of 0.1N CH3COOH is ( dissociation constant = 10^-5) a) 10^-5 b) 10^-4 c) 10^-3 d) 10^-2?.
Order of dissociation of 0.1N CH3COOH is ( dissociation constant = 10^-5) a) 10^-5 b) 10^-4 c) 10^-3 d) 10^-2? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Order of dissociation of 0.1N CH3COOH is ( dissociation constant = 10^-5) a) 10^-5 b) 10^-4 c) 10^-3 d) 10^-2? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Order of dissociation of 0.1N CH3COOH is ( dissociation constant = 10^-5) a) 10^-5 b) 10^-4 c) 10^-3 d) 10^-2?.
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