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What volume of hydrogen gas at 273 K and 1 atm pressure will be consumed in obtaining 21.6 g of elemental boron ( atomic mass= 10.8) from the reduction of boron trichloride by hydrogen ? a)67.2 L b)44.8 L c)22.4 L d)89.6 L?
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To determine the volume of hydrogen gas consumed in obtaining 21.6 g of elemental boron from the reduction of boron trichloride by hydrogen, we can use the stoichiometry of the reaction.
The balanced equation for the reaction is:
BCl₃ + 3H₂ → B + 3HCl
From the equation, we can see that 1 mole of boron trichloride reacts with 3 moles of hydrogen gas to produce 1 mole of boron.
1) Calculate the moles of boron:
Molar mass of boron = 10.8 g/mol
Moles of boron = mass of boron / molar mass of boron
Moles of boron = 21.6 g / 10.8 g/mol
Moles of boron = 2 mol
2) Determine the moles of hydrogen gas required:
From the balanced equation, we know that 1 mole of boron requires 3 moles of hydrogen gas.
Moles of hydrogen gas = 3 moles of boron
Moles of hydrogen gas = 3 mol
3) Use the ideal gas law to calculate the volume of hydrogen gas:
PV = nRT
Where:
P = pressure (1 atm)
V = volume
n = moles of gas (3 mol)
R = ideal gas constant (0.0821 L·atm/mol·K)
T = temperature (273 K)
Rearranging the equation to solve for V:
V = (nRT) / P
V = (3 mol)(0.0821 L·atm/mol·K)(273 K) / 1 atm
V = 67.2 L
Therefore, the volume of hydrogen gas consumed in obtaining 21.6 g of elemental boron is 67.2 L.
The correct answer is a) 67.2 L.
The balanced equation for the reaction is:
BCl₃ + 3H₂ → B + 3HCl
From the equation, we can see that 1 mole of boron trichloride reacts with 3 moles of hydrogen gas to produce 1 mole of boron.
1) Calculate the moles of boron:
Molar mass of boron = 10.8 g/mol
Moles of boron = mass of boron / molar mass of boron
Moles of boron = 21.6 g / 10.8 g/mol
Moles of boron = 2 mol
2) Determine the moles of hydrogen gas required:
From the balanced equation, we know that 1 mole of boron requires 3 moles of hydrogen gas.
Moles of hydrogen gas = 3 moles of boron
Moles of hydrogen gas = 3 mol
3) Use the ideal gas law to calculate the volume of hydrogen gas:
PV = nRT
Where:
P = pressure (1 atm)
V = volume
n = moles of gas (3 mol)
R = ideal gas constant (0.0821 L·atm/mol·K)
T = temperature (273 K)
Rearranging the equation to solve for V:
V = (nRT) / P
V = (3 mol)(0.0821 L·atm/mol·K)(273 K) / 1 atm
V = 67.2 L
Therefore, the volume of hydrogen gas consumed in obtaining 21.6 g of elemental boron is 67.2 L.
The correct answer is a) 67.2 L.
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What volume of hydrogen gas at 273 K and 1 atm pressure will be consumed in obtaining 21.6 g of elemental boron ( atomic mass= 10.8) from the reduction of boron trichloride by hydrogen ? a)67.2 L b)44.8 L c)22.4 L d)89.6 L?
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What volume of hydrogen gas at 273 K and 1 atm pressure will be consumed in obtaining 21.6 g of elemental boron ( atomic mass= 10.8) from the reduction of boron trichloride by hydrogen ? a)67.2 L b)44.8 L c)22.4 L d)89.6 L? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about What volume of hydrogen gas at 273 K and 1 atm pressure will be consumed in obtaining 21.6 g of elemental boron ( atomic mass= 10.8) from the reduction of boron trichloride by hydrogen ? a)67.2 L b)44.8 L c)22.4 L d)89.6 L? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What volume of hydrogen gas at 273 K and 1 atm pressure will be consumed in obtaining 21.6 g of elemental boron ( atomic mass= 10.8) from the reduction of boron trichloride by hydrogen ? a)67.2 L b)44.8 L c)22.4 L d)89.6 L?.
What volume of hydrogen gas at 273 K and 1 atm pressure will be consumed in obtaining 21.6 g of elemental boron ( atomic mass= 10.8) from the reduction of boron trichloride by hydrogen ? a)67.2 L b)44.8 L c)22.4 L d)89.6 L? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about What volume of hydrogen gas at 273 K and 1 atm pressure will be consumed in obtaining 21.6 g of elemental boron ( atomic mass= 10.8) from the reduction of boron trichloride by hydrogen ? a)67.2 L b)44.8 L c)22.4 L d)89.6 L? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What volume of hydrogen gas at 273 K and 1 atm pressure will be consumed in obtaining 21.6 g of elemental boron ( atomic mass= 10.8) from the reduction of boron trichloride by hydrogen ? a)67.2 L b)44.8 L c)22.4 L d)89.6 L?.
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