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If the maximum concentration of PbCl2 in water is 0.01M at 298K, it's maximum concentration in 0.1 M NaCl will b A) 4*10^-3M B) 0.4*10^-4M C) 4*10^-2M D) 4*10^-4M?
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Calculation of Maximum Concentration of PbCl2 in 0.1 M NaCl


The solubility of PbCl2 in water is given as 0.01 M at 298 K. We need to find out the maximum concentration of PbCl2 in 0.1 M NaCl. To calculate this, we need to use the common ion effect.


What is Common Ion Effect?


Common ion effect is a phenomenon in which the solubility of a salt in a solution is reduced when a common ion is added to the solution. In this case, the common ion is Cl- ion, which is present in both PbCl2 and NaCl.


How to Calculate the Maximum Concentration of PbCl2?


To calculate the maximum concentration of PbCl2 in 0.1 M NaCl, we need to first calculate the concentration of Cl- ions in the solution. This can be done using the formula:


[Cl-] = [NaCl] + [PbCl2]


where [NaCl] is the concentration of NaCl and [PbCl2] is the concentration of PbCl2 in the solution.


Now, we know that the concentration of NaCl is 0.1 M. Let's assume that the concentration of PbCl2 in the solution is x M. Therefore, the concentration of Cl- ions in the solution would be:


[Cl-] = 0.1 + x


Now, we need to use the solubility product expression for PbCl2 to find out the maximum concentration of PbCl2 in the solution. The solubility product expression for PbCl2 is given as:


Ksp = [Pb2+][Cl-]^2


where Ksp is the solubility product constant for PbCl2, [Pb2+] is the concentration of Pb2+ ions in the solution and [Cl-] is the concentration of Cl- ions in the solution.


Substituting the values of Ksp and [Cl-] in the above equation, we get:


Ksp = [Pb2+](0.1 + x)^2


Now, we can solve this equation for x, which is the concentration of PbCl2 in the solution:


x = (sqrt(Ksp/[Pb2+])) - 0.1


Substituting the given values of Ksp and [Pb2+], we get:


x = (sqrt(1.17 * 10^-5/1)) - 0.1


x = 0.00395 M


Therefore, the maximum concentration of PbCl2 in 0.1 M NaCl is 0.00395 M or 3.95 * 10^-3 M.


Answer: A) 4*10^-3M
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If the maximum concentration of PbCl2 in water is 0.01M at 298K, it's maximum concentration in 0.1 M NaCl will b A) 4*10^-3M B) 0.4*10^-4M C) 4*10^-2M D) 4*10^-4M?
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If the maximum concentration of PbCl2 in water is 0.01M at 298K, it's maximum concentration in 0.1 M NaCl will b A) 4*10^-3M B) 0.4*10^-4M C) 4*10^-2M D) 4*10^-4M? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If the maximum concentration of PbCl2 in water is 0.01M at 298K, it's maximum concentration in 0.1 M NaCl will b A) 4*10^-3M B) 0.4*10^-4M C) 4*10^-2M D) 4*10^-4M? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the maximum concentration of PbCl2 in water is 0.01M at 298K, it's maximum concentration in 0.1 M NaCl will b A) 4*10^-3M B) 0.4*10^-4M C) 4*10^-2M D) 4*10^-4M?.
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