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In family liliaceae flowers are -
  • a)
    Trimerous and hypogynous
  • b)
    Pentamerous and epigynous
  • c)
    Trimerous and epigynous
  • d)
    Pentamerous and hypogynous
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
In family liliaceae flowers are -a)Trimerous and hypogynousb)Pentamero...
Liliaceae flowers - Hermaphroditic, actinomorphic (radially symmetric) or slightly zygomorphic (bilaterally symmetric), pedicellate (on a short secondary stem), generally large and showy but may be inconspicuous (Medeoleae). Bracts may (bracteate) or may not (ebracteate) be present. The perianth is undifferentiated (perigonium) and biseriate (two whorled), formed from six tepals arranged into two separate whorls of three parts (trimerous) each, although Scoliopus has only three petals, free from the other parts, but overlapping.
Liliaceae gynoecium - Superior ovary (hypogynous), syncarpous (with fused carpels), with three connate (fused) carpels and is trilocular (three locules, or chambers) or unilocular (single locule, as in Scoliopus and Medeola). There is a single style and a three lobed stigma or three stigmata more or less elongated along the style. There are numerous anatropous (curved) ovules which display axile placentation (parietal in Scoliopus and Medeola), usually with an integument and thinner megasporangium. 
Therefore, the correct answer is option A
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Most Upvoted Answer
In family liliaceae flowers are -a)Trimerous and hypogynousb)Pentamero...
The family Liliaceae.... the floral formula consist of Gynoecium which are tricarpellary and ovary are superior in position (hypogynous).
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Community Answer
In family liliaceae flowers are -a)Trimerous and hypogynousb)Pentamero...
I think option d I'd the right answer because liliaceae is the dicot flowering plant in this case pentamerous type is happen
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In family liliaceae flowers are -a)Trimerous and hypogynousb)Pentamerous and epigynousc)Trimerous and epigynousd)Pentamerous and hypogynousCorrect answer is option 'A'. Can you explain this answer?
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