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A alpha particle moves toward a rest nucleus. if kinetic energy of alpha particle is 10MeV and atomic number of nucleus is 50.the closest approach will be?
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A alpha particle moves toward a rest nucleus. if kinetic energy of alp...
Calculation of Closest Approach of Alpha Particle to a Rest Nucleus


Given


  • Kinetic energy of alpha particle = 10 MeV

  • Atomic number of the nucleus = 50



Formula Used


  • Distance of closest approach (r) = (1.44 x Z1 x Z2 x e^2) / (K x A^0.5) where, Z1 and Z2 are atomic numbers of alpha particle and nucleus, e is the charge of an electron, K is the Coulomb's constant, and A is the mass number of the nucleus.



Calculation


  • Z1 = 2 (as alpha particle has 2 protons)

  • Z2 = 50 (given atomic number of the nucleus)

  • e = 1.6 x 10^-19 C (charge of an electron)

  • K = 8.99 x 10^9 Nm^2/C^2 (Coulomb's constant)

  • A = mass number of the nucleus, which is not given. However, we can assume it to be 100 (a reasonable approximation for a nucleus with atomic number of 50).



Using these values in the formula, we get:

r = (1.44 x 2 x 50 x (1.6 x 10^-19)^2) / (10 x 100^0.5) = 1.13 x 10^-14 m

Therefore, the closest approach of the alpha particle to the rest nucleus is 1.13 x 10^-14 m.

Explanation

When an alpha particle approaches a nucleus, it experiences electrostatic repulsion due to the positive charges on both. The kinetic energy of the alpha particle allows it to overcome this repulsion and get close to the nucleus. However, at some point, the repulsive force becomes too great and the alpha particle is pushed away. This point is known as the closest approach. The distance of closest approach depends on the kinetic energy of the alpha particle, the atomic numbers of the alpha particle and nucleus, and the mass number of the nucleus. The formula used above takes these factors into account to calculate the distance of closest approach.
Community Answer
A alpha particle moves toward a rest nucleus. if kinetic energy of alp...
is 0 right??because electrostatic as well as gravitational both the forces are attractive
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