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Resistance of 0.2 M solution of an electrolyte is 50 Ω. The specific conductance of the solution is 1.4 S m–1. The resistance of 0.5 M solution of the same electrolyte is 280 Ω. The molar conductivity of 0.5 M solution of the electrolyte in S m2 mol–1 is:
- a)5 × 10–4
- b)5 × 10–3
- c)5 × 103
- d)5 × 102
Correct answer is option 'A'. Can you explain this answer?
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Resistance of 0.2 M solution of an electrolyte is 50 Ω. The speci...
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Resistance of 0.2 M solution of an electrolyte is 50 Ω. The speci...
To find the molar conductivity of the 0.5 M solution of the electrolyte, we can use the formula:
Molar conductivity = (Specific conductance × 1000) / Concentration
Given that the specific conductance of the solution is 1.4 S m^-1 and the concentration is 0.2 M, we can calculate the molar conductivity as follows:
Molar conductivity = (1.4 × 1000) / 0.2 = 7000 S m^2 mol^-1
Now, we need to find the resistance of the 0.5 M solution of the same electrolyte. Given that the resistance of the 0.2 M solution is 50 Ω, we can use the formula:
Resistance = (Specific resistivity × Length) / Area
Since the length and area of the cell are the same for both solutions, we can write:
Resistance of 0.2 M solution = (Specific resistivity × Length) / Area
Resistance of 0.5 M solution = (Specific resistivity × Length) / Area
Dividing these two equations, we get:
(Resistance of 0.2 M solution) / (Resistance of 0.5 M solution) = (Specific resistivity of 0.2 M solution) / (Specific resistivity of 0.5 M solution)
Given that the resistance of the 0.2 M solution is 50 Ω and the resistance of the 0.5 M solution is 280 Ω, we can substitute these values into the equation and solve for the specific resistivity ratio:
(50) / (280) = (Specific resistivity of 0.2 M solution) / (Specific resistivity of 0.5 M solution)
Specific resistivity of 0.5 M solution = (Specific resistivity of 0.2 M solution) × (280 / 50)
Now, we know that the specific conductance is the reciprocal of specific resistivity:
Specific resistivity = 1 / Specific conductance
Substituting this into the equation, we get:
Specific resistivity of 0.5 M solution = (1 / Specific conductance of 0.2 M solution) × (280 / 50)
Given that the specific conductance of the 0.2 M solution is 1.4 S m^-1, we can substitute this value into the equation and solve for the specific resistivity of the 0.5 M solution:
Specific resistivity of 0.5 M solution = (1 / 1.4) × (280 / 50) = 4
Now, we need to find the molar conductivity of the 0.5 M solution using the specific resistivity:
Molar conductivity = (1 / Specific resistivity) × 1000 = (1 / 4) × 1000 = 250 S m^2 mol^-1
Therefore, the correct answer is option A: 5 × 10^4 S m^2 mol^-1.
Molar conductivity = (Specific conductance × 1000) / Concentration
Given that the specific conductance of the solution is 1.4 S m^-1 and the concentration is 0.2 M, we can calculate the molar conductivity as follows:
Molar conductivity = (1.4 × 1000) / 0.2 = 7000 S m^2 mol^-1
Now, we need to find the resistance of the 0.5 M solution of the same electrolyte. Given that the resistance of the 0.2 M solution is 50 Ω, we can use the formula:
Resistance = (Specific resistivity × Length) / Area
Since the length and area of the cell are the same for both solutions, we can write:
Resistance of 0.2 M solution = (Specific resistivity × Length) / Area
Resistance of 0.5 M solution = (Specific resistivity × Length) / Area
Dividing these two equations, we get:
(Resistance of 0.2 M solution) / (Resistance of 0.5 M solution) = (Specific resistivity of 0.2 M solution) / (Specific resistivity of 0.5 M solution)
Given that the resistance of the 0.2 M solution is 50 Ω and the resistance of the 0.5 M solution is 280 Ω, we can substitute these values into the equation and solve for the specific resistivity ratio:
(50) / (280) = (Specific resistivity of 0.2 M solution) / (Specific resistivity of 0.5 M solution)
Specific resistivity of 0.5 M solution = (Specific resistivity of 0.2 M solution) × (280 / 50)
Now, we know that the specific conductance is the reciprocal of specific resistivity:
Specific resistivity = 1 / Specific conductance
Substituting this into the equation, we get:
Specific resistivity of 0.5 M solution = (1 / Specific conductance of 0.2 M solution) × (280 / 50)
Given that the specific conductance of the 0.2 M solution is 1.4 S m^-1, we can substitute this value into the equation and solve for the specific resistivity of the 0.5 M solution:
Specific resistivity of 0.5 M solution = (1 / 1.4) × (280 / 50) = 4
Now, we need to find the molar conductivity of the 0.5 M solution using the specific resistivity:
Molar conductivity = (1 / Specific resistivity) × 1000 = (1 / 4) × 1000 = 250 S m^2 mol^-1
Therefore, the correct answer is option A: 5 × 10^4 S m^2 mol^-1.
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Resistance of 0.2 M solution of an electrolyte is 50 Ω. The specific conductance of the solution is 1.4 S m–1. The resistance of 0.5 M solution of the same electrolyte is 280 Ω. The molar conductivity of 0.5 M solution of the electrolyte in S m2 mol–1 is:a)5 × 10–4b)5 × 10–3c)5 × 103d)5 × 102Correct answer is option 'A'. Can you explain this answer?
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Resistance of 0.2 M solution of an electrolyte is 50 Ω. The specific conductance of the solution is 1.4 S m–1. The resistance of 0.5 M solution of the same electrolyte is 280 Ω. The molar conductivity of 0.5 M solution of the electrolyte in S m2 mol–1 is:a)5 × 10–4b)5 × 10–3c)5 × 103d)5 × 102Correct answer is option 'A'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Resistance of 0.2 M solution of an electrolyte is 50 Ω. The specific conductance of the solution is 1.4 S m–1. The resistance of 0.5 M solution of the same electrolyte is 280 Ω. The molar conductivity of 0.5 M solution of the electrolyte in S m2 mol–1 is:a)5 × 10–4b)5 × 10–3c)5 × 103d)5 × 102Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Resistance of 0.2 M solution of an electrolyte is 50 Ω. The specific conductance of the solution is 1.4 S m–1. The resistance of 0.5 M solution of the same electrolyte is 280 Ω. The molar conductivity of 0.5 M solution of the electrolyte in S m2 mol–1 is:a)5 × 10–4b)5 × 10–3c)5 × 103d)5 × 102Correct answer is option 'A'. Can you explain this answer?.
Resistance of 0.2 M solution of an electrolyte is 50 Ω. The specific conductance of the solution is 1.4 S m–1. The resistance of 0.5 M solution of the same electrolyte is 280 Ω. The molar conductivity of 0.5 M solution of the electrolyte in S m2 mol–1 is:a)5 × 10–4b)5 × 10–3c)5 × 103d)5 × 102Correct answer is option 'A'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Resistance of 0.2 M solution of an electrolyte is 50 Ω. The specific conductance of the solution is 1.4 S m–1. The resistance of 0.5 M solution of the same electrolyte is 280 Ω. The molar conductivity of 0.5 M solution of the electrolyte in S m2 mol–1 is:a)5 × 10–4b)5 × 10–3c)5 × 103d)5 × 102Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Resistance of 0.2 M solution of an electrolyte is 50 Ω. The specific conductance of the solution is 1.4 S m–1. The resistance of 0.5 M solution of the same electrolyte is 280 Ω. The molar conductivity of 0.5 M solution of the electrolyte in S m2 mol–1 is:a)5 × 10–4b)5 × 10–3c)5 × 103d)5 × 102Correct answer is option 'A'. Can you explain this answer?.
Solutions for Resistance of 0.2 M solution of an electrolyte is 50 Ω. The specific conductance of the solution is 1.4 S m–1. The resistance of 0.5 M solution of the same electrolyte is 280 Ω. The molar conductivity of 0.5 M solution of the electrolyte in S m2 mol–1 is:a)5 × 10–4b)5 × 10–3c)5 × 103d)5 × 102Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
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ample number of questions to practice Resistance of 0.2 M solution of an electrolyte is 50 Ω. The specific conductance of the solution is 1.4 S m–1. The resistance of 0.5 M solution of the same electrolyte is 280 Ω. The molar conductivity of 0.5 M solution of the electrolyte in S m2 mol–1 is:a)5 × 10–4b)5 × 10–3c)5 × 103d)5 × 102Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice Chemistry tests.
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