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For the reaction :C+CO2 -> 2CO The partial pressure of CO2 and CO is 2.0 and 4.0 atm respectively at equilibrium .then Kp for the reaction is A. 0.5 B. 4.0 C. 8.0 D .32.0?
Most Upvoted Answer
For the reaction :C+CO2 -> 2CO The partial pressure of CO2 and CO is 2...
Given:
The reaction is : C + CO2 -> 2CO
The partial pressure of CO2 at equilibrium is 2.0 atm.
The partial pressure of CO at equilibrium is 4.0 atm.

To Find:
The value of Kp for the reaction.

Explanation:
The equilibrium constant Kp for a reaction is defined as the ratio of the partial pressures of the products raised to their stoichiometric coefficients to the partial pressures of the reactants raised to their stoichiometric coefficients.

The balanced equation for the reaction is:
C + CO2 -> 2CO

According to the stoichiometry of the reaction, the stoichiometric coefficients are:
C: 1
CO2: 1
CO: 2

So, the expression for Kp can be written as:
Kp = (P_CO)^2 / (P_CO2 * P_C)

Given that the partial pressure of CO2 at equilibrium is 2.0 atm and the partial pressure of CO at equilibrium is 4.0 atm, we can substitute these values into the expression for Kp.

Kp = (4.0)^2 / (2.0 * P_C)

Simplifying the expression:
Kp = 16.0 / (2.0 * P_C)
Kp = 8.0 / P_C

Since we don't know the partial pressure of C, we can't calculate the exact value of Kp. However, we can determine the relationship between Kp and the partial pressure of C.

Answer:
The value of Kp for the given reaction is 8.0/P_C.
So, the correct option is C. 8.0.
Community Answer
For the reaction :C+CO2 -> 2CO The partial pressure of CO2 and CO is 2...
We know Kp = partial pressure or product / partial pressure of reactant
here C is solid Co2 and Co is gas
that's why Kp = P(CO)^2/P(CO2)
= 4^2/2 =16/2=8 ans.
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For the reaction :C+CO2 -> 2CO The partial pressure of CO2 and CO is 2.0 and 4.0 atm respectively at equilibrium .then Kp for the reaction is A. 0.5 B. 4.0 C. 8.0 D .32.0?
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