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In excitable cells, re-polarization is closely associated 
with one of the following events
  • a)
     efflux
  • b)
     influx
  • c)
     efflux
  • d)
     influx
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
In excitable cells, re-polarization is closely associatedwith one of t...
Simply we can remind as
deplorisation as Na+ influx..
repolorisation as K+ efflux..
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Community Answer
In excitable cells, re-polarization is closely associatedwith one of t...
Re-polarization in Excitable Cells

In excitable cells, such as neurons and muscle cells, action potentials are generated and transmitted. These action potentials are caused by the movement of ions across the cell membrane.

During an action potential, the cell membrane becomes depolarized as sodium ions enter the cell. This depolarization causes the cell to become more positive, which then triggers the opening of voltage-gated potassium channels.

Re-polarization

Re-polarization is the process by which the cell membrane returns to its resting potential after an action potential has occurred. This process is closely associated with the efflux of potassium ions from the cell.

K Efflux

Efflux means the outward flow. During re-polarization, the voltage-gated potassium channels that opened during depolarization allow K+ ions to flow out of the cell, which causes the membrane potential to become more negative.

As more potassium ions leave the cell, the membrane potential becomes more negative, and the cell returns to its resting state. This process of re-polarization allows the cell to generate another action potential if needed.

Conclusion

In conclusion, re-polarization in excitable cells is closely associated with the efflux of potassium ions from the cell. This process allows the cell to return to its resting potential and generate another action potential if needed.
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In excitable cells, re-polarization is closely associatedwith one of the following eventsa) effluxb)influxc)effluxd) influxCorrect answer is option 'C'. Can you explain this answer?
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