NEET Exam > NEET Questions > Two elements X having atomic weight=75 and Y ...
Start Learning for Free
Two elements X having atomic weight=75 and Y having atomic weight=16 combine to give a compound having 75.8% of X.The emperical formula of a compound is- 1)XY 2)X2Y 3)X2Y2 4)X2Y3?
Most Upvoted Answer
Two elements X having atomic weight=75 and Y having atomic weight=16 c...
Community Answer
Two elements X having atomic weight=75 and Y having atomic weight=16 c...
Explanation:
The given problem is about finding the empirical formula of a compound formed by two elements X and Y. The atomic weight of X is 75, and the atomic weight of Y is 16. The compound is composed of 75.8% of X. We need to determine the empirical formula of the compound.
Calculating the molecular weight of the compound:
Let us assume that the compound contains 100 grams of the substance. Since the compound is composed of 75.8% of X, the mass of X in the compound will be 75.8 grams. Similarly, the mass of Y in the compound will be 100 - 75.8 = 24.2 grams.
The number of moles of X can be determined by dividing the mass of X by its atomic weight, which is 75 g/mol. Therefore, the number of moles of X in the compound is 75.8/75 = 1.01 moles.
The number of moles of Y can be determined by dividing the mass of Y by its atomic weight, which is 16 g/mol. Therefore, the number of moles of Y in the compound is 24.2/16 = 1.51 moles.
The molecular weight of the compound can be determined by adding the product of the number of moles of each element and its atomic weight. Therefore, the molecular weight of the compound is:
(1.01 x 75) + (1.51 x 16) = 133.27 g/mol
Determining the empirical formula:
The empirical formula of a compound is the simplest ratio of atoms in the compound. To determine the empirical formula of the compound, we need to divide the molecular weight of the compound by the atomic weight of each element and then simplify the ratio.
The atomic weight of X is 75, and its contribution to the molecular weight is 75.8/133.27 = 0.568. The atomic weight of Y is 16, and its contribution to the molecular weight is 16/133.27 = 0.120.
Dividing each of these values by the smallest value gives the following ratios:
X: 0.568/0.120 = 4.73
Y: 0.120/0.120 = 1
Therefore, the empirical formula of the compound is X4.73Y, which can be simplified to X2Y.
Answer:
The empirical formula of the compound formed by the elements X and Y with atomic weights of 75 and 16, respectively, is X2Y.
The given problem is about finding the empirical formula of a compound formed by two elements X and Y. The atomic weight of X is 75, and the atomic weight of Y is 16. The compound is composed of 75.8% of X. We need to determine the empirical formula of the compound.
Calculating the molecular weight of the compound:
Let us assume that the compound contains 100 grams of the substance. Since the compound is composed of 75.8% of X, the mass of X in the compound will be 75.8 grams. Similarly, the mass of Y in the compound will be 100 - 75.8 = 24.2 grams.
The number of moles of X can be determined by dividing the mass of X by its atomic weight, which is 75 g/mol. Therefore, the number of moles of X in the compound is 75.8/75 = 1.01 moles.
The number of moles of Y can be determined by dividing the mass of Y by its atomic weight, which is 16 g/mol. Therefore, the number of moles of Y in the compound is 24.2/16 = 1.51 moles.
The molecular weight of the compound can be determined by adding the product of the number of moles of each element and its atomic weight. Therefore, the molecular weight of the compound is:
(1.01 x 75) + (1.51 x 16) = 133.27 g/mol
Determining the empirical formula:
The empirical formula of a compound is the simplest ratio of atoms in the compound. To determine the empirical formula of the compound, we need to divide the molecular weight of the compound by the atomic weight of each element and then simplify the ratio.
The atomic weight of X is 75, and its contribution to the molecular weight is 75.8/133.27 = 0.568. The atomic weight of Y is 16, and its contribution to the molecular weight is 16/133.27 = 0.120.
Dividing each of these values by the smallest value gives the following ratios:
X: 0.568/0.120 = 4.73
Y: 0.120/0.120 = 1
Therefore, the empirical formula of the compound is X4.73Y, which can be simplified to X2Y.
Answer:
The empirical formula of the compound formed by the elements X and Y with atomic weights of 75 and 16, respectively, is X2Y.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
Two elements X having atomic weight=75 and Y having atomic weight=16 combine to give a compound having 75.8% of X.The emperical formula of a compound is- 1)XY 2)X2Y 3)X2Y2 4)X2Y3?
Question Description
Two elements X having atomic weight=75 and Y having atomic weight=16 combine to give a compound having 75.8% of X.The emperical formula of a compound is- 1)XY 2)X2Y 3)X2Y2 4)X2Y3? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two elements X having atomic weight=75 and Y having atomic weight=16 combine to give a compound having 75.8% of X.The emperical formula of a compound is- 1)XY 2)X2Y 3)X2Y2 4)X2Y3? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two elements X having atomic weight=75 and Y having atomic weight=16 combine to give a compound having 75.8% of X.The emperical formula of a compound is- 1)XY 2)X2Y 3)X2Y2 4)X2Y3?.
Two elements X having atomic weight=75 and Y having atomic weight=16 combine to give a compound having 75.8% of X.The emperical formula of a compound is- 1)XY 2)X2Y 3)X2Y2 4)X2Y3? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two elements X having atomic weight=75 and Y having atomic weight=16 combine to give a compound having 75.8% of X.The emperical formula of a compound is- 1)XY 2)X2Y 3)X2Y2 4)X2Y3? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two elements X having atomic weight=75 and Y having atomic weight=16 combine to give a compound having 75.8% of X.The emperical formula of a compound is- 1)XY 2)X2Y 3)X2Y2 4)X2Y3?.
Solutions for Two elements X having atomic weight=75 and Y having atomic weight=16 combine to give a compound having 75.8% of X.The emperical formula of a compound is- 1)XY 2)X2Y 3)X2Y2 4)X2Y3? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of Two elements X having atomic weight=75 and Y having atomic weight=16 combine to give a compound having 75.8% of X.The emperical formula of a compound is- 1)XY 2)X2Y 3)X2Y2 4)X2Y3? defined & explained in the simplest way possible. Besides giving the explanation of
Two elements X having atomic weight=75 and Y having atomic weight=16 combine to give a compound having 75.8% of X.The emperical formula of a compound is- 1)XY 2)X2Y 3)X2Y2 4)X2Y3?, a detailed solution for Two elements X having atomic weight=75 and Y having atomic weight=16 combine to give a compound having 75.8% of X.The emperical formula of a compound is- 1)XY 2)X2Y 3)X2Y2 4)X2Y3? has been provided alongside types of Two elements X having atomic weight=75 and Y having atomic weight=16 combine to give a compound having 75.8% of X.The emperical formula of a compound is- 1)XY 2)X2Y 3)X2Y2 4)X2Y3? theory, EduRev gives you an
ample number of questions to practice Two elements X having atomic weight=75 and Y having atomic weight=16 combine to give a compound having 75.8% of X.The emperical formula of a compound is- 1)XY 2)X2Y 3)X2Y2 4)X2Y3? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup