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Two elements X having atomic weight=75 and Y having atomic weight=16 combine to give a compound having 75.8% of X.The emperical formula of a compound is- 1)XY 2)X2Y 3)X2Y2 4)X2Y3?
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Two elements X having atomic weight=75 and Y having atomic weight=16 c...
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Two elements X having atomic weight=75 and Y having atomic weight=16 c...
Explanation:
The given problem is about finding the empirical formula of a compound formed by two elements X and Y. The atomic weight of X is 75, and the atomic weight of Y is 16. The compound is composed of 75.8% of X. We need to determine the empirical formula of the compound.
Calculating the molecular weight of the compound:
Let us assume that the compound contains 100 grams of the substance. Since the compound is composed of 75.8% of X, the mass of X in the compound will be 75.8 grams. Similarly, the mass of Y in the compound will be 100 - 75.8 = 24.2 grams.
The number of moles of X can be determined by dividing the mass of X by its atomic weight, which is 75 g/mol. Therefore, the number of moles of X in the compound is 75.8/75 = 1.01 moles.
The number of moles of Y can be determined by dividing the mass of Y by its atomic weight, which is 16 g/mol. Therefore, the number of moles of Y in the compound is 24.2/16 = 1.51 moles.
The molecular weight of the compound can be determined by adding the product of the number of moles of each element and its atomic weight. Therefore, the molecular weight of the compound is:
(1.01 x 75) + (1.51 x 16) = 133.27 g/mol
Determining the empirical formula:
The empirical formula of a compound is the simplest ratio of atoms in the compound. To determine the empirical formula of the compound, we need to divide the molecular weight of the compound by the atomic weight of each element and then simplify the ratio.
The atomic weight of X is 75, and its contribution to the molecular weight is 75.8/133.27 = 0.568. The atomic weight of Y is 16, and its contribution to the molecular weight is 16/133.27 = 0.120.
Dividing each of these values by the smallest value gives the following ratios:
X: 0.568/0.120 = 4.73
Y: 0.120/0.120 = 1
Therefore, the empirical formula of the compound is X4.73Y, which can be simplified to X2Y.
Answer:
The empirical formula of the compound formed by the elements X and Y with atomic weights of 75 and 16, respectively, is X2Y.
The given problem is about finding the empirical formula of a compound formed by two elements X and Y. The atomic weight of X is 75, and the atomic weight of Y is 16. The compound is composed of 75.8% of X. We need to determine the empirical formula of the compound.
Calculating the molecular weight of the compound:
Let us assume that the compound contains 100 grams of the substance. Since the compound is composed of 75.8% of X, the mass of X in the compound will be 75.8 grams. Similarly, the mass of Y in the compound will be 100 - 75.8 = 24.2 grams.
The number of moles of X can be determined by dividing the mass of X by its atomic weight, which is 75 g/mol. Therefore, the number of moles of X in the compound is 75.8/75 = 1.01 moles.
The number of moles of Y can be determined by dividing the mass of Y by its atomic weight, which is 16 g/mol. Therefore, the number of moles of Y in the compound is 24.2/16 = 1.51 moles.
The molecular weight of the compound can be determined by adding the product of the number of moles of each element and its atomic weight. Therefore, the molecular weight of the compound is:
(1.01 x 75) + (1.51 x 16) = 133.27 g/mol
Determining the empirical formula:
The empirical formula of a compound is the simplest ratio of atoms in the compound. To determine the empirical formula of the compound, we need to divide the molecular weight of the compound by the atomic weight of each element and then simplify the ratio.
The atomic weight of X is 75, and its contribution to the molecular weight is 75.8/133.27 = 0.568. The atomic weight of Y is 16, and its contribution to the molecular weight is 16/133.27 = 0.120.
Dividing each of these values by the smallest value gives the following ratios:
X: 0.568/0.120 = 4.73
Y: 0.120/0.120 = 1
Therefore, the empirical formula of the compound is X4.73Y, which can be simplified to X2Y.
Answer:
The empirical formula of the compound formed by the elements X and Y with atomic weights of 75 and 16, respectively, is X2Y.
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Two elements X having atomic weight=75 and Y having atomic weight=16 combine to give a compound having 75.8% of X.The emperical formula of a compound is- 1)XY 2)X2Y 3)X2Y2 4)X2Y3?
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Two elements X having atomic weight=75 and Y having atomic weight=16 combine to give a compound having 75.8% of X.The emperical formula of a compound is- 1)XY 2)X2Y 3)X2Y2 4)X2Y3? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two elements X having atomic weight=75 and Y having atomic weight=16 combine to give a compound having 75.8% of X.The emperical formula of a compound is- 1)XY 2)X2Y 3)X2Y2 4)X2Y3? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two elements X having atomic weight=75 and Y having atomic weight=16 combine to give a compound having 75.8% of X.The emperical formula of a compound is- 1)XY 2)X2Y 3)X2Y2 4)X2Y3?.
Two elements X having atomic weight=75 and Y having atomic weight=16 combine to give a compound having 75.8% of X.The emperical formula of a compound is- 1)XY 2)X2Y 3)X2Y2 4)X2Y3? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two elements X having atomic weight=75 and Y having atomic weight=16 combine to give a compound having 75.8% of X.The emperical formula of a compound is- 1)XY 2)X2Y 3)X2Y2 4)X2Y3? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two elements X having atomic weight=75 and Y having atomic weight=16 combine to give a compound having 75.8% of X.The emperical formula of a compound is- 1)XY 2)X2Y 3)X2Y2 4)X2Y3?.
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