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1.5 moles of O2 combines with Mg to form oxide MgO the mass of mg that has combined is- 1)72 g 2)36g 3)24g 4)94g?
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1.5 moles of O2 combines with Mg to form oxide MgO the mass of mg that...
Calculation of Mass of Mg that has Combined with O2 to form MgO

Given data:
Moles of O2 = 1.5 mol
Formula of MgO = Mg + O2 → MgO
Molecular mass of MgO = 40.31 g/mol
Molecular mass of Mg = 24.31 g/mol

Step 1: Write the balanced chemical equation for the reaction
Mg + O2 → MgO

Step 2: Calculate the moles of MgO formed
From the balanced chemical equation, it is clear that 1 mole of Mg reacts with 1 mole of O2 to form 1 mole of MgO.
Therefore, 1.5 moles of O2 will react with 1.5 moles of Mg to form 1.5 moles of MgO.

Step 3: Calculate the mass of MgO formed
Molecular mass of MgO = 40.31 g/mol
Mass of 1.5 moles of MgO = 40.31 x 1.5 = 60.465 g

Step 4: Calculate the mass of Mg that has combined with O2
From the balanced chemical equation, we know that 1 mole of Mg reacts with 1 mole of O2 to form 1 mole of MgO.
Therefore, the moles of Mg that has combined with 1.5 moles of O2 to form 1.5 moles of MgO is also 1.5 moles.

Molecular mass of Mg = 24.31 g/mol
Mass of 1.5 moles of Mg = 24.31 x 1.5 = 36.465 g

Therefore, the mass of Mg that has combined with O2 to form MgO is 36.465 g.

Answer: 2) 36g
Community Answer
1.5 moles of O2 combines with Mg to form oxide MgO the mass of mg that...
2Mg+O2 -------- 2MgO

So 1 mole of oxygen react with 2 moles of Mg .

1.5 moles of oxygen react with 3 moles of Mg.

We have 1mole of Mg =24.31 g

3 moles of Mg =24.31×3 = 72.93g

Thus 1.5 mole Oxygen required 72.93 g of Mg
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1.5 moles of O2 combines with Mg to form oxide MgO the mass of mg that has combined is- 1)72 g 2)36g 3)24g 4)94g?
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