Hot metal at 1700 K is poured in a sand mould that is open at the top....
**Explanation:**
When hot metal at a temperature of 1700 K is poured into a sand mold, heat loss from the liquid metal occurs through three modes - radiation, conduction, and convection.
**1. Radiation:**
Radiation is the transfer of heat energy through electromagnetic waves. In this case, the hot metal at 1700 K will radiate heat energy as infrared radiation. This radiation will be emitted from the surface of the metal and will be absorbed by the surrounding environment, including the sand mold. Thus, heat loss through radiation will occur.
**2. Conduction:**
Conduction is the transfer of heat energy through direct contact between objects. When the hot metal comes into contact with the sand mold, heat will be conducted from the metal to the mold. This is because the metal has a higher temperature than the mold, and heat naturally flows from a higher temperature to a lower temperature. Therefore, heat loss through conduction will also occur.
**3. Convection:**
Convection is the transfer of heat energy through the movement of fluids (liquid or gas). In this case, the air surrounding the hot metal and the sand mold will be heated by the metal. As a result, the air will become less dense and rise, creating a convection current. As the hot air rises, cooler air from the surroundings will come into contact with the metal, absorbing heat from it. This process will continue, resulting in the transfer of heat energy from the metal to the surrounding environment. Hence, heat loss through convection will take place.
Therefore, when hot metal at 1700 K is poured into a sand mold that is open at the top, heat loss will occur through all three modes - radiation, conduction, and convection. Thus, the correct answer is option 'D' - Radiation, conduction, and convection.