Two pipes x and y can fill a cistern in 24 minute and 32 min. res. If ...
Let y be closed after a minutes.
acc to ques,
part filled by (x+y) in a min= a/24+a/32
part filled by X in (18-a)min=(18-a)×1/24
together,
a/24+a/32+(18-a)1/24=1
on solving,
a=8
Y should be closed after 8 mins.
Two pipes x and y can fill a cistern in 24 minute and 32 min. res. If ...
To solve this problem, we need to find the rate at which each pipe fills the cistern and then use that information to determine when to close pipe y.
Let's assume that the cistern has a capacity of 1 unit.
Rate of pipe x = 1/24 units per minute
Rate of pipe y = 1/32 units per minute
If both pipes are opened together, their combined rate is:
Rate of both pipes = (1/24) + (1/32) = 8/192 + 6/192 = 14/192 = 7/96 units per minute
Now, we need to find the time it takes for the cistern to be filled in 18 minutes.
Let's assume that pipe y is closed after t minutes.
In the first 18 minutes, pipe x and y together fill:
(7/96) x 18 = 7/96 x 18/1 = 7/96 x 18 = 7/32 units
Since the cistern has a capacity of 1 unit, the remaining amount that needs to be filled is:
1 - 7/32 = 32/32 - 7/32 = 25/32 units
Let's assume that pipe y is closed after t minutes. In that case, pipe x will continue to fill the cistern for (18 - t) minutes.
The amount of water filled by pipe x in (18 - t) minutes is:
(1/24) x (18 - t) = (18 - t)/24 units
Now, we can set up the equation:
(18 - t)/24 = 25/32
To solve for t, we can cross-multiply:
32(18 - t) = 24(25)
576 - 32t = 600
-32t = 600 - 576
-32t = 24
t = 24/32
t = 3/4
Therefore, pipe y should be closed after 3/4 minutes, which is equivalent to 45 seconds or 0.75 minutes.
Hence, the correct answer is option 'C' - 8 minutes.