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If 4 tan theta=3 ,evaluate 4sin theta -cos theta 1/4 sin theta -cos theta-1?
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If 4 tan theta=3 ,evaluate 4sin theta -cos theta 1/4 sin theta -cos t...
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Finding the value of sin(theta) and cos(theta)


We are given that 4 tan theta = 3. We can use the identity tan^2(theta) + 1 = sec^2(theta) to find the value of cos(theta) and sin(theta).


First, we can square both sides of the equation 4 tan theta = 3 to get:


16 tan^2 theta = 9


Then, we can substitute tan^2(theta) with sec^2(theta) - 1 to get:


16(sec^2(theta) - 1) = 9


Simplifying this equation, we get:


16 sec^2(theta) - 16 = 9


Adding 16 to both sides, we get:


16 sec^2(theta) = 25


Dividing both sides by 16, we get:


sec^2(theta) = 25/16


Taking the square root of both sides, we get:


sec(theta) = 5/4


Now, we can use the identity sec^2(theta) = 1/cos^2(theta) to find the value of cos(theta):


cos^2(theta) = 1/sec^2(theta)


cos^2(theta) = 16/25


cos(theta) = +/- 4/5


Since 4 tan(theta) = 3, we know that tan(theta) = 3/4. Using the identity tan^2(theta) + 1 = sec^2(theta), we can find the value of sin(theta):


tan^2(theta) + 1 = sec^2(theta)


(3/4)^2 + 1 = (5/4)^2


9/16 + 1 = 25/16


sin^2(theta) = 16/25


sin(theta) = +/- 4/5


Since cos(theta) and sin(theta) have opposite signs, we know that cos(theta) = -4/5 and sin(theta) = 3/5.


Finding the value of 4sin(theta) - cos(theta)


Now that we have found the values of sin(theta) and cos(theta), we can use them to evaluate the expression 4sin(theta) - cos(theta).


4sin(theta) - cos(theta) = 4(3/5) - (-4/5)


4sin(theta) - cos(theta) = 12/5 + 4/5


4sin(theta) - cos(theta) = 16/5


Finding the value of 1/4sin(theta) - cos(theta) - 1


Now we can use the value we found above to evaluate the expression 1/4sin(theta) - cos(theta) - 1.


Community Answer
If 4 tan theta=3 ,evaluate 4sin theta -cos theta 1/4 sin theta -cos t...
4 tan=3                                                                            since tan=3/4                                                              now,                   
Tan=perpendicular/base 
So,tan=3/4
Now, 
Hypotenuse= root 3^+4^
=root 9+16
=root 25
=5
Using this we can find ,
Sin= perpendicular/hypotenuse =3/5
Cos=base/hypotenuse =4/5
A.C.T.P:
(4sin theta_ cos+1)/(4sin theta+ cos_1)
=(4�3/5_4/5+1)/(4�3/5+4/5_1)
= (12_4+5)/(12+4_5)
=13/11 
In place of question mark keep multiplication symbol(�)
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